Answer:
-1
This is because in negative the numbers the higher the number, the lower its value
Step-by-step explanation:
Where is the rest of the question
1.02 is the answer to your question
Answer:
7(b^2 -2)(b^2 +2)
Step-by-step explanation:
Factoring the common factor 7 from both terms, you get the difference of squares. That can also be factored.
v = 7(b^4 -4) = 7(b^2 -2)(b^2 +2)
The difference b^2-2 will have irrational factors, so does not meet the problem requirements. This is the factorization over integers.