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Leno4ka [110]
3 years ago
6

Dorlanic's birthday party is coming up on Saturday. His friend Isaiah says there is a chance that he will attend the party. How

likely is it
that Isaiah will attend?
O A It is certain that Isaiah will attend.
OB. It is impossible that Isaiah will attend.
OC. It is likely that Isaiah will attend.
O D. It is neither likely nor unlikely that Isaiah will attend.
Mathematics
2 answers:
steposvetlana [31]3 years ago
5 0

Answer:

c. its likely that Isaiah will attend

Step-by-step explanation:

im sorry if im wrong just wanted to help, but it just seems like the right choice

Andreyy893 years ago
3 0
I think it’s C I’m not sure
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Find the number of elements in A 1 ∪ A 2 ∪ A 3 if there are 200 elements in A 1 , 1000 in A 2 , and 5, 000 in A 3 if (a) A 1 ⊆ A
lina2011 [118]

Answer:

a. 4600

b. 6200

c. 6193

Step-by-step explanation:

Let n(A) the number of elements in A.

Remember, the number of elements in A_1 \cup A_2 \cup A_3 satisfies

n(A_1 \cup A_2 \cup A_3)=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)

Then,

a) If A_1\subseteq A_2, n(A_1 \cap A_2)=n(A_1)=200, and if A_2\subseteq A_3, n(A_2\cap A_3)=n(A_2)=1000

Since A_1\subseteq A_2\; and \; A_2\subseteq A_3, \; then \; A_1\cap A_2 \cap A_3= A_1

So

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-200-200-1000-200=4600

b) Since the sets are pairwise disjoint

n(A_1 \cup A_2 \cup A_3)=\\n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\200+1000+5000-0-0-0-0=6200

c) Since there are two elements in common to each pair of sets and one element in all three sets, then

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-2-2-2-1=6193

8 0
3 years ago
I need help showing my work for the answer.
user100 [1]

Answer: ong

Step-by-step explanation: im straight

4 0
3 years ago
Assume that all interest is simple interestBerger Car rental borrow $8500 at 4% interest to cover the increase cost of the auto
viva [34]

we know that

The formula of simple interest is equal to

I=P(rt)

In this problem

we have

I=$170

P=$8,500

r=4%=4/100=0.04

t=?

substitute given values in the formula

\begin{gathered} 170=8,500(0.04t) \\ Solve\text{ for t} \\ t=\frac{170}{8,500*0.04} \\ t=0.5\text{ years} \end{gathered}

therefore

0.5 years=6 months

<h2>The answer is 6 months</h2>
5 0
1 year ago
Jean bought a $1,980 snow thrower on the installment plan. The installment agreement included a 10% down payment and 18 monthly
enyata [817]

Answer:

Jean paid $2,286 for the snow thrower, with a finance charge of $306.

Step-by-step explanation:

Given that Jean bought a $ 1,980 snow thrower through an initial payment of 10% of the initial value, and 18 monthly payments of $ 116, to determine the final price paid by Jean, the following calculation is required:

(1,980 x 0.1) + (18 x 116) = X

198 + 2,088 = X

2,286 = X

Therefore, the final price paid for Jean was $ 2,286.

In turn, the finance charge arises from the difference between the final price and the list price, that is:

2,286 - 1,980 = X

306 = X

Thus, the finance charge is $ 306.

8 0
3 years ago
Which explanation provides the best real-world senario of the graph​
VikaD [51]

Answer:

i don't know

Step-by-step explanation:

4 0
3 years ago
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