The expression is a bit invalid. You can't add variables by variables.
Answer:
No
Reasoning:
If something is a perfect cube, it is able to be put under a cube root (![\sqrt[3]{..}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B..%7D)
) and will result in an integer (a non-decimal number > 0, basically).
So let's calculate ![\sqrt[3]{48}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D)
, and see if the result is an integer.
= 3.634.......
As you can see, the result is not an integer, therefore 48 is not a perfect cube.
There are a lot of numbers you can think of, for example, 1030, or even 9939, but I don't recommend you put that ;)
68 can go into 757 11 times, the remainder would be 9
757÷68= 11 r 9 or 11 9/68
Answer:
g(x) = -|x| + 1
Step-by-step explanation:
Let g(x) be the transformation function
-|x| reflects f(x) across the x-axis. Add 1 to move the result up one unit
So, g(x) = -|x| + 1
