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LUCKY_DIMON [66]
3 years ago
15

What are the factors of m2 – 12m + 20?

Mathematics
1 answer:
o-na [289]3 years ago
3 0

For this case we must factor the following expression:

m ^ 2-12m + 20

To factor, we look for two numbers that, when multiplied, result in 20 and when added, result in -12.

These numbers are: -10 and -2.

-10-2 = -12\\-10 * -2 = 20

Thus, we factor the expression as:

(m-10) (m-2)

Answer:

The factors of the given expression are:

(m-10) (m-2)

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54

Step-by-step explanation:

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A cube has a volume of 343 cubic cm. What is the area of the base
Amanda [17]

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49 cm²

Step-by-step explanation:

The volume (V) of a cube is calculated as

V = s³ ← s is the length of the side, thus

s³ = 343 ( take the cube root of both sides )

s = \sqrt[3]{343} = 7, thus

area of base = s² = 7² = 49 cm²

6 0
3 years ago
When pay rate is $14/hr and an employee has a 15 minutes added to an hour, how much?
hram777 [196]

Answer:

$3.50

Step-by-step explanation:

15 min is 1/4 hr.

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3 years ago
How do you do series with an n
SOVA2 [1]
The problem can be solved step by step, if we know certain basic rules of summation.  Following rules assume summation limits are identical.
\sum{a+b}=\sum{a}+\sum{b}
\sum{kx}=k\sum{x}
\sum_{r=1}^n{1}=n
\sum_{r=1}^n{r}=n(n+1)/2

Armed with the above rules, we can split up the summation into simple terms:
\sum_{r=1}^n{40r-21n+8}=n
=40\sum_{r=1}^n{r}-21n\sum_{r=1}^n{1}+8\sum_{r=1}^n{1}
=40\frac{n(n+1)}{2}-21n^2+8n
=20n(n+1)-21n^2+8n
=28n-n^2

=> (a) f(x)=28n-n^2
=> f'(x)=28-2n 
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0  therefore f(14) is a maximum
(b) f(x) is a maximum when n=14

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4 0
3 years ago
7(n+4) ....................
Juli2301 [7.4K]

Answer:

<h2>7n + 28</h2>

Step-by-step explanation:

7(n + 4)

Expand

7 \times n = 7n \\ 7 \times 4 = 28 \\  \\ 7n + 28

4 0
3 years ago
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