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Charra [1.4K]
3 years ago
10

I need help with 4ourth grade math lesson 8 homework helper asap math

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
3 0

Answer:

sure

Step-by-step explanation:

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A scientist measured the width of a square flake of gold to be7.3 x 10 -4mm what is the area of the flake
irakobra [83]

The area of square flake of gold is 53.29 \times 10^{-8} \mathrm{mm}

<h3><u>Solution:</u></h3>

Given that width of square flake of gold is 7.3 \times 10^{-4} millimeter

To find : Area of square flake

Since gold flake is in shape of square, we can use area of square formula

<em><u>The formula for area of square is given as:</u></em>

area = s^2

where "s" is the length of one side

\begin{array}{l}{\text { Area of a square flake }=\left(7.3 \times 10^{-4}\right) \times\left(7.3 \times 10^{-4}\right)} \\\\ {\text { Area of a square flake }=53.29 \times 10^{8}}\end{array}

Hence , the calculated area of flake is 53.29 \times 10^{-8} \mathrm{mm}

7 0
3 years ago
If h(x) equals negative 7 (x minus 8 ) plus 2 find the value of h (negative 5)
vichka [17]

Answer:

h = -7x - 11

Step-by-step explanation:

6 0
2 years ago
Which vertex will result in the maximum value of the function T = x – 3y?
exis [7]

Answer:

(0,-3) will give the maximum value

Step-by-step explanation:

To know the vertex, we have to substitute the coordinates in the options

we have this as follows

a) (1.5,0)

T = 1.5-3(0) = -1.5

b) (3.5,4)

T = 3.5 - 1)4)

= 3.5 - 4 = -0.5

c) (0,-3)

we have

T = 0-3(-3) = 0 + 9 = 9

d) (0,4)

we have this as:

T = 0 - 3(4) = -12

7 0
3 years ago
Original cost at $9.99 at discount at 15% with a sales tax 5%
enyata [817]
Hope this helps but I think the answer is $8.91.

4 0
3 years ago
Read 2 more answers
128.09 to the nearest tenth
vaieri [72.5K]

Answer:

128.1

Step-by-step explanation:

Since this is rounding to the nearest tenth , we look at the first number after the decimal place it's 0 so we look at the second number after the decimal place which is 9 , this rounds 0 up to 1

8 0
3 years ago
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