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Debora [2.8K]
3 years ago
5

When pay rate is $14/hr and an employee has a 15 minutes added to an hour, how much?

Mathematics
1 answer:
hram777 [196]3 years ago
6 0

Answer:

$3.50

Step-by-step explanation:

15 min is 1/4 hr.

Working an add'l 1/4 hr brings the employee additional pay:

($14/hr)(1/4  hr)  = $7/2, or $3.50

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a girl 2.2m tall observes that the angle of elevation of the top of a building 16m away from her is 45° find the height of the b
Anika [276]

Answer:

wigggle

Step-by-step explanation:

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5 0
3 years ago
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PIC INCLUDED PLS RESPOND FAST WILL MARK BRAINLIEST
serg [7]

Answer:

the correct answer is -5/8.

7 0
2 years ago
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Can someone help me on this?
Vinil7 [7]

Answer:

12√2

Step-by-step explanation:

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Where both the sides that are across from the same angle (45) are equal in length and the hypotenuse is that value multiplied by the √2

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(problem 83)
AVprozaik [17]

To find the derivative of this function, there is a property that we should know called the Constant Multiple Rule, which says:

\dfrac{d}{dx}[cf(x)] = cf'(x) (where c is a constant)


Remember that the derivative of \csc(x) is -\csc(x)\cot(x). However, you may notice that we are finding the derivative of \dfrac{1}{2}\csc(2x), not \dfrac{1}{2} \csc(x). So, we are going to have to use the chain rule. To complete the chain rule for the derivative of a trigonometric function (in layman's terms) is basically the following: First, complete the derivative of the trig function as you would if what was inside the trig function is x. Then, take the derivative of what's inside of the trig function and multiply it by what you found in the first step.


Let's apply that to our problem. Right now, I am not going to worry about the \dfrac{1}{2} at the front of the equation, since we can just multiply it back in at the end of our problem. So, let's examine \csc(2x). We see that what's inside the trig function is 2x, which has a derivative of 2. Thus, let's first find the derivative of \csc(2x) as if 2x was just x and then multiply it by 2.


The derivative of \csc(2x) would first be -\cot(2x)\csc(2x). Multiplying it by 2, we get our derivative of -2\cot(2x)\csc(2x). However, don't forget to multiply it by the \dfrac{1}{2} that we removed near the beginning. This gives us our final derivative of -\cot(2x)\csc(2x).


Remember that we now have to find the derivative at the given point. To do this, simply "plug in" the point into the derivative using the x-coordinate. This is shown below:

-\cot[2(\dfrac{\pi}{4})]\csc[2(\dfrac{\pi}{4})]

-\cot(\dfrac{\pi}{2})\csc(\dfrac{\pi}{2})

-(0)(1) = \boxed{0}


Our final answer is 0.

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