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3 years ago

5

When pay rate is $14/hr and an employee has a 15 minutes added to an hour, how much?

1 answer:

hram777 [196]3 years ago

6 0

Answer:

$3.50

Step-by-step explanation:

15 min is 1/4 hr.

Working an add'l 1/4 hr brings the employee additional pay:

($14/hr)(1/4 hr) = $7/2, or $3.50

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HURRY ASAP PLZZZZ ANYONE???? There are 25 towns in a certain country, and every pair of them is connected by a train route. How

Julli [10]

Answer:

25 train routes

Step-by-step explanation:

The train routes go from 1-2, 2-3, 3-4, 4-5, ,and so on, but there is also one that goes from 25-1. If you notice, there when we get to 4-5, there are 4 train routes which means that if there are 25 towns, then there are 24 train routes, but since 25 and 1 are connected then there are 25 routes. Hope this helps!

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4 years ago

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Juanita saved 35% of the money that she needs to buy a bycicle. If she saved $98 how much money does the bycicle cost?

spayn [35]

Answer:

$280

Step-by-step explanation:

35%=$98 (to find 1%: 98/35) 1%=$2.8 100%=$280

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3 years ago

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What is the solution set of 2x(x - 1) = 3?

garik1379 [7]

First you must distribute the 2x to the numbers inside the parentheses

(2x * x) + (2x * -1) = 3

$2x^{2}$ - 2x = 3

To make this a quadratic equation you can solve bring the 3 over to the left side of the equation by subtracting it to both sides

$2x^{2}$ - 2x - 3 = 0

Use the quadratic equation to solve this (image of the quadratic equation is below)

Remember that quadratic functions are set up like so:

$ax^{2} +bx +c = 0$

That means that in this equation...

a = 2

b = -2

c = -3

^^^Plug these numbers into the quadratic equation and solve...

$\frac{2+/-\sqrt{(-2)^{2}-4(2)(-3)}}{2(2)}$

$\frac{2 +/-\sqrt{4+24}}{4}$

$\frac{2+/-\sqrt{28} }{4}$

$\frac{2+/-2\sqrt{7} }{4}$

$\frac{1+/-\sqrt{7} }{2}$

Keep in mind that +/- is ±

$\frac{1+\sqrt{7} }{2}$

$\frac{1-\sqrt{7} }{2}$

^^^Exact answers

Approximations:

1.823

-0.823

Hope this helped!

~Just a girl in love with Shawn Mendes

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3 years ago

PLEASE ANSWER WILL GIVE POINTS!!!!!!!!!!!

iris [78.8K]

Given:

The figure of a right triangle ABC.

To find:

The trigonometric ratios $\sin B, \tan A, \cos B$ .

Solution:

Using Pythagoras theorem,

$Hypotenuse^2=Perpendicular^2+Base^2$

$AB^2=AC^2+BC^2$

$(10)^2=(6)^2+BC^2$

$100-36=BC^2$

$64=BC^2$

Taking square root on both sides.

$\sqrt{64}=BC$

$8=BC$

So, measure of BC is 8 units.

Now,

$\sin \theta=\dfrac{Opposite}{Hypotenuse}$

$\sin B=\dfrac{AC}{AB}$

$\sin B=\dfrac{6}{10}$

$\sin B=\dfrac{3}{5}$

Similarly,

$\tan \theta=\dfrac{Opposite}{Adjacent}$

$\tan A=\dfrac{AC}{BC}$

$\tan A=\dfrac{6}{8}$

$\tan A=\dfrac{3}{4}$

And,

$\cos \theta=\dfrac{Adjacent}{Hypotenuse}$

$\cos B=\dfrac{BC}{AB}$

$\cos B=\dfrac{8}{10}$

$\cos B=\dfrac{4}{5}$

Therefore, the required trigonometric ration are $\sin B=\dfrac{3}{5}, \tan A=\dfrac{3}{4}, \cos B=\dfrac{4}{5}$ .

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3 years ago

Which equation is a function?

kaheart [24]

Option C I think???????

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3 years ago

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