Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,

Here,
,Perpendicular AB = 4000


Solving for BC, we get,

(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
Answer:
The playground is 160ft by 360ft.
The model is 4in by 9in
First, 1ft = 12 inches.
Then the measures of the playground, in inches, is:
160*12in = 1920 in
360*12in = 4320in
The playground is 1920in by 4320in.
Then, the ratios between the measures of the playground and the model are:
1920in/4in = 480
4320in/9in = 480
This means that each inch in the model, represents 480 inches in the actual playground.
<span>If the slope of the ppf is same between any two points, it implies that the opportunity costs did not change and they were constant. So the constant slope implies that production possibilities frontier appears to be a straight line with the opportunity costs being constant.</span>
n can be all the way upto 7 as 8 x4 = 32 which is higher than 30. The lowest possible diggit is 1.
n = 1, 2, 3, 4, 5, 6, 7
1 + 2 + 3 + 4 + 5 + 6 + 7 = 28
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Answer:
0.78
Step-by-step explanation:
We have the next probability distribution:
X P(X)
0 0.2
1 0.3
2 0.5
As we can see when we add all the probabilites the result is 1. Now calculating the mean we have:

The standard deviation is:

Then using the data that we have:

Then the standard deviation is 0.78