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konstantin123 [22]
4 years ago
15

Which of the following is a monomial?

Mathematics
2 answers:
timama [110]4 years ago
6 0

For this case we have that by definition, a monomial is an algebraic expression that consists of a single term. The parts of a monomial are: Coefficient and literal part

That said, we have to give the options given, the monomio is given by:

-8c

Where "c" is the literal part and -8 the coefficient.

Answer:

Option C

Alex787 [66]4 years ago
4 0
It is c2+c+6 .......
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Plzzzz help asap
vlabodo [156]
(x,y) or
(x,f(x))
so just plug the first value in and see if yo get the 2nd value


A. when x=-2, then is f(x)=48?
remember, x^-m=1/(x^m)
3(1/4)^-2=3/((1/4)^2)=3/(1/16)=3*16=48
true

B. x^0=1
so 3(1/4)^0=3(1)=3
true

C. when x=2
3(1/4)^2, 3(1/16), 3/16
true

D. 12
das is obviously false but anyway
3(1/4)^12=3(1/big number)=3/big number=small number but not zero



answer is A,B,C
5 0
3 years ago
The digit 5 appears twice in the number 255,120. How does the total value of the 5 on the right compare to the total value of th
maksim [4K]

Answer:

The value of the first "5" in the number 255,\!120 is ten times that of the second "5\!" in this number.

Step-by-step explanation:

What gives the number "255,\!120" its value? Of course, each of its six digits has contributed. However, their significance are not exactly the same. For example, changing the first \verb!5! to \verb!6! would give 2\mathbf{6}5,\!120 and increase the value of this number by 10,\!000. On the other hand, changing the second \verb!5!\! to \verb!6!\! would give 25\mathbf{6},\!120, which is an increase of only 1,\!000 compared to the original number.

The order of these two digits matter because the number "255,\!120" is written using positional notation. In this notation, the position of each digits gives the digit a unique weight. For example, in 255,\!120\!:

\begin{array}{|r||c|c|c|c|c|c|}\cline{1-7}\verb!Digit!& \verb!2! & \verb!5! & \verb!5! & \verb!1! & \verb!2! & \verb!0!\\\cline{1-7}\textsf{Index} & 5 & 4 & 3 & 2 & 1& 0 \\ \cline{1-7} \textsf{Weight} & 10^{5} & 10^{4} & 10^{3} & 10^{2} & 10^{1} & 10^{0}\\\cline{1-7}\end{array}.

(Note that the index starts at 0 from the right-hand side.)

Using these weights, the value 255,\!120 can be written as the sum:

\begin{aligned}& 255,\!120\\ &= 2 \times 10^{5} + 5 \times 10^{4} + 5 \times 10^{3} + 1 \times 10^{2} + 2 \times 10^{1} + 0 \times 10^{0} \\&=200,\!000 + 50,\!000 + 5,\!000 + 100 + 20 + 0 \end{aligned}.

As seen in this sum, the first "5" contributed 50,\!000 to the total value, while the second "5\!" contributed only 5,\!000.

Hence: The value of the first "5" in the number 255,\!120 is ten times that of the second "5\!" in this number.  

7 0
4 years ago
Read 2 more answers
Is the inequality always, sometimes, or never true?<br> 3x - 14 &lt; 3(x-5)
lys-0071 [83]

Answer:

3x - 14 < 3x - 15

-14 < -15

never true

Step-by-step explanation:

8 0
4 years ago
What is the first step in solving the quadratic equation -5x2+8=133
astraxan [27]
I don’t think you can solve by using quadratic equation

4 0
3 years ago
What is y=mx+b solve for x
Hitman42 [59]

Answer:

equation of a line

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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