Answer:
Dividing both sides of 5x = 4 by 5 yields x = 4 _. 5 . The value of x can now be ... tuting −1 for a into the equation b = –a + 3 gives b = −(−1) + 3, or b = 4. ... ___. 82 − (2i)2 . Since i2 = −1, this can be simplified to 24 − 6i − 40i − 10. __.
hope this helps also Brainliest please:)
Well this is simple a calculator type problem...but if you are curious as the the algorithm used by simple calculators and such...
They use a Newtonian approximation until it surpasses the precision level of the calculator or computer program..
A newtonian approximation is an interative process that gets closer and closer to the actual answer to any mathematical problem...it is of the form:
x-(f(x)/(df/dx))
In a square root problem you wish to know:
x=√n where x is the root and n is the number
x^2=n
x^2-n=0
So f(x)=x^2-n and df/dx=2x so using the definition of the newton approximation you have:
x-((x^2-n)/(2x)) which simplifies further to:
(2x^2-x^2+n)/(2x)
(x^2+n)/(2x), where you can choose any starting value of x that you desire (though convergence to an exact (if possible) solution will be swifter the closer xi is to the actual value x)
In this case the number, n=95.54, so a decent starting value for x would be 10.
Using this initial x in (x^2+95.54)/(2x) will result in the following iterative sequence of x.
10, 9.777, 9.774457, 9.7744565, 9.7744565066299210578124802523397
The calculator result for my calc is: 9.7744565066299210578124802523381
So you see how accurate the newton method is in just a few iterations. :P
Each variable used is the first letter of each of their names.
t+b+c=87
c=2t
b=t+7
Substitute for b and c
t+ (t+7)+2t= 87
4t+7=87
4t=80
t=20
Plug in the known t value.
c=2(20)
c=40
b=20+7
b=27
Final answer: Tammy=$20, Boris= $27, Carlos=$40
Answer:
D
Step-by-step explanation:
Parallel lines must have the same slope. They <em>could</em> have points in common. If the y-intercepts were the same, taking into consideration the fact that the slopes have to be the same, it would be the same line and as the question directs, they are not. Parallel lines can have negative slope, as long as their slopes are equal.
