A line passes through (2, –1) and (8, 4). a. Write an equation for the line in point-slope form. b. Rewrite the equation in stan dard form using integers
1 answer:
The point-slope form of a line is: y-y1=m(x-x1), where m=slope and (x1,y1) is any point on the line First we need to find the slope, which is (y2-y1)/(x2-x1) m=(4--1)/(8-2) m=5/6 and we can use either point, I'll use (8,4) y-4=(5/6)(x-8) That is your equation in point-slope form. Now the standard equation of a line is ax+by=c y-4=(5/6)(x-8) we can perform the indicated multiplication on the right side y-4=(5x-40)/6 multiply both sides by 6 6y-24=5x-40 add 24 to both sides 6y=5x-16 subtract 5x from both sides -5x+6y=-16 and by convention, the standard equation of a line should be expressed with a positive coefficient for x, so multiply both sides by -1 5x-6y=16
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576 I hope this help cause I did this two years ago so I'm a little rusty but I think this is correct
Answer:
x=-1/2
Step-by-step explanation:
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Answer:
A i think bc its the only one that makes since
For this case, the first thing we must do is define variables: x = number of quarters y = number of dimes We now write the system of equations: x + y = 28 0.25x + 0.10y = 4.05 Solving the system of equations we have: x = 8.33 y = 19.66 Rounding: x = 8 y = 20 Answer: the college student has: 8 quarters 20 dimes
<span>The LCM is 21624..Hope This Helps You! Good Luck Studying :) </span>