First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
Answer:
Explanation:
Volume = 1/3(area of base) times height. 1/3(PI X R(squared)) X height. 1/3 x 3.14 x 25 x 6 = 157
<em>Hope this helps and have a great day/night!</em>
<em> -</em><em><u>grey</u></em>
Answer:
Step-by-step explanation:
Converse
Your answer would be $11.50 I hope this helps you out! :)
