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olga nikolaevna [1]
1 year ago
7

Find the surface area of the composite figure.

Mathematics
1 answer:
Sloan [31]1 year ago
7 0

With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.

<h3>What is the surface area of a truncated prism?</h3>

The <em>surface</em> area of the <em>truncated</em> prism is the sum of the areas of its six faces, which are combinations of the areas of rectangles and <em>right</em> triangles. Then, we proceed to determine the <em>surface</em> area:

A = (12 cm) · (4 cm) + 2 · (3 cm) · (4 cm) + 2 · (12 cm) · (3 cm) + 2 · 0.5 · (12 cm) · (5 cm) + (5 cm) · (4 cm) + (13 cm) · (4 cm)

A = 48 cm² + 24 cm² + 72 cm² + 60 cm² + 20 cm² + 52 cm²

A = 276 cm²

With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.

To learn more on surface areas: brainly.com/question/2835293

#SPJ1

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Answer:

\frac{x^2+2x}{x-3}

Step-by-step explanation:

We need to factor out numerator and denominator in order to simplify the rational expression by cancelling  common factors.

Numerator :  x^3 - 4 x = x (x^2 - 4) = x (x - 2) (x + 2)

Denominator (factoring by grouping):

x^2 - 5 x + 6 = x^2 - 3 x - 2 x + 6 = x (x - 3) - 2 (x - 3) = (x - 3) (x - 2)

Then we can cancel out the common factor (x - 2) in both numerator and denominator, leading to:

x (x + 2) / (x - 3) = (x^2 + 2)/ (x-3)

\frac{x^2+2x}{x-3}

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Triangle X Y Z is cut by line segment C D. Line segment C D goes from side X Y to side Y Z. The length of C D is 15, the length
Marizza181 [45]

The length of DZ is 4 units ⇒ 3rd answer

Step-by-step explanation:

Triangle X Y Z is cut by line segment C D, where

  • C lies on side XY and D lies on the side YZ
  • The length of C D is 15
  • The length of X Z is 18
  • The length of C Y is 25
  • The length of Y D is 20
  • C D and X Z are parallel
  • CX = 5 units

We need to find the length of DZ

In Δ XYZ

∵ C ∈ XY and D ∈ YZ

∵ CD // XZ

∴ m∠YCD = m∠YXZ ⇒ alternate angles

∴ m∠YDC = m∠YZX ⇒ alternate angles

In Δs YCD and YXZ

∵ m∠YCD = m∠YXZ

∵ m∠YDC = m∠YZX

∵ ∠Y is a common angle

∴ Δ YCD is similar to Δ YXZ by AAA postulate

- There is a constant ratio between their corresponding sides

∴ \frac{YC}{YX}=\frac{CD}{XZ}=\frac{YD}{YZ}

∵ YC = 25 units

∵ CX = 5 units

∵ YX = YC + CX

∴ YX = 25 + 5 = 30 units

∵ YD = 20 units

∵ YZ = YD + DZ

∴ YZ = 20 + DZ

Let us use the ratio of the corresponding side

∵ \frac{YC}{YX}=\frac{YD}{YZ}

∴ \frac{25}{30}=\frac{20}{20+DZ}

- Simplify \frac{25}{30} by dividing up and down by 5

∵ \frac{25}{30}=\frac{5}{6}

∴ \frac{5}{6}=\frac{20}{20+DZ}

- By using cross multiplication

∴ 5(20 + DZ) = 6(20)

∴ 100 + 5 DZ = 120

- Subtract 100 from both sides

∴ 5 DZ = 20

- Divide both sides by 5

∴ DZ = 4 units

The length of DZ is 4 units

Learn more:

You can learn more about triangles in brainly.com/question/3202836

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