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3 years ago

12

Alfonso and Lucas are 238 miles apart, traveling towards each other. If Lucas travels 21 mph and Alfonso travels 13 mph how long

until they meet?

1 answer:

Alex3 years ago

7 0

Lucas equation for his location is x(t) = 13t.

Alfonso's equation is x(t) = 238 - 21t

If you equate these, you get:

13t = 238 - 21t =>

34t = 238

t = 7

So after seven hours they meet.

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a

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The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

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$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

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$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

$SE = 0.0186$

The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

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$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

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$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

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The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

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