Question

According to a study done by De Anza students, the height for Asian adult males is normally distributed with an average of 66 inches and a standard deviation of 2.5 inches. Suppose one Asian adult male is randomly chosen. Let X = height of the individual.

Answer 1

Answer:

The probability that the person is between 65 and 69 inches is 0.5403

Step-by-step explanation:

Mean height = $\mu = 66$

Standard deviation = $\sigma = 2.5$

We are supposed to find What is the probability that the person is between 65 and 69 inches i.e.P(65<x<69)

$Z=\frac{x-\mu}{\sigma}$

At x = 65

$Z=\frac{65-66}{2.5}$

Z=-0.4

Refer the z table for p value

P(x<65)=0.3446

At x = 69

$Z=\frac{69-66}{2.5}$

Z=1.2

P(x<69)=0.8849

So,P(65<x<69)=P(x<69)-P(x<65)=0.8849-0.3446=0.5403

Hence the probability that the person is between 65 and 69 inches is 0.5403