A = w*l
5/8 = w*10
w = (5/8)/10 = (5/8)*(1/10) = 5/80 = 1/16
w=1/16
From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is

, and

.
There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.
That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are

and

. The difference of those two cubes is:

In our problem, a = 4 (since

= 64) and b = y (since

. Plug these values into the rule to find the factor of

:

-----
Answer:
(9/18)(9/18) = 81/324. The probability that Amy takes out pink chips in both draws is 81/324.
In this example we will use the probability property P(A∩B), which means given two independent events A and B, their joint probability P(A∩B) can be expressed as the product of the individual probabilities P(A∩B) = P(A)P(B).
The total number of chips of different colors in Amy's bag is:
8 blue chips + 9 pink chips + 1 white chip = 18 color chips
Amy takes out a chip from the bag randomly without looking, she replaces the chip and then takes out another chip from the bag.
So, the probability that Amy takes out a pink chip in the first draw is:
P(A) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.
Then, Amy replaces the chip an takes out another which means there are again 18 color chips divide into 8 blue chips, 9 pink chips, and 1 white chip. So, the probability of takes out a pink chip in the second draw is:
P(B) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.
What is the probability that Amy takes out a pink chip in both draws?
P(A∩B) = P(A)P(B)
P(A∩B) = (9/18)(9/18) = 81/324
Answer:
The $1 belongs to the cash box
Step-by-step explanation:
Given
See attachment for complete question
Required
Determine if the $1 belongs to the cash box or not
Represent singles with s and couples with c.
From the attachment, we have:
--- total attendance
--- ticket sold
Solve for s and c.
Make s the subject in (1)

Substitute 47 - c for s in (2)

Open bracket




This means that the total individual which makes up the couples are 35. This is not possible because couples are in 2's and the total should be an even number.
<em>So, we can conclude that the $1 belongs to the cash box</em>