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3 years ago

I need this, help please

Mathematics

1 answer:

pychu [463]3 years ago

8 0

Answer:

W or the letter choice c

Step-by-step explanation:

Since it says (8,5), on the x line start at 0 and count to eight. Since the Y is five, go up 5 while being on that 8 and there you go, its W

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Mr. Charles gave both of his sons, Joe and Bill, $5,000. Joe deposited the money in an account that offered simple interest of 1

Maksim231197 [3]

Answer:

Bill by $85

Step-by-step explanation:

Bill : Compound interest is calculated by multiplying the initial principal amount by one plus the annual interest rate raised to the number of compound periods minus one. The total initial amount of the money given is then subtracted from the resulting value.

Compounded annually for 6 years at 9 % interest Bill would have $8385.50.

Joe : Simple interest at 11% a year The formula we'll use for this is the simple interest formula.

P is the principal amount, $5000.00.

r is the interest rate, 11% per year, or in decimal form, 11/100=0.11.

t is the time involved, 6year(s) time periods.

So, t is 6year time periods.

To find the simple interest, we multiply 5000 × 11 × 6 = 3300

Usually now, the interest is added onto the principal to figure some new amount after 6 year(s),

or 5000.00 + 3300.00 = 8300.00

As you can see Bill has more by $85.

^Check yourself

5 0

3 years ago

HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work

Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) $8+6x^4$

here we can see, both numbers are divisible by 2, so taking 2 common

$=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)$

It cannot be further simplified because both number donot have same bases.

3. $4n^9 + 12 n$

We can take 4n common

$=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)$

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. $12n^5 + 16n^3$

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

$4n^3( 3n^2 + 4)$

9. $5k^2 - 40k+10$

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

$=5(k^2 - 8k + 2)$

11. $-60 + 60n^2 +50n^3$

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

$=10(-6 + 6n^2 +5n^3)$

13. $-36n^3 -12n-28$

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

$=-4(9n^3 + 3n +7)$

15. $63n^3+81n+18$

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

$=9(7n^3 + 9n + 2)$