First, change one of the equations to an y=x form I'll use the top one for example.
3x-2y=14
-2y=14-3x
y=-7+(3/2)x
Not that you can show what y is in terms of x, plug in the x side of the equation into the other equation, for y.
x+2(-7+(3/2)x)=10
Now, you can solve for x
x-14+3x=10
4x-14=10
4x=24
x=6
Using this value of x, we can now solve for y using one of the original equations.
(6)+2y=10
2y=4
y=2
A: Division
you would take the 438/15 to find out how many teams there are
Answer:
1. the range of f^-1(x) is {10, 20, 30}.
2. the graph of f^-1(x) will include the point (0, 3)
3. n = 8
Step-by-step explanation:
1. The domain of a function is the range of its inverse, and vice versa. The range of f^-1(x) is {10, 20, 30}.
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2. See above. The domain and range are swapped between a function and its inverse. That means function point (3, 0) will correspond to inverse function point (0, 3).
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3. The n-th term of an arithmetic sequence is given by ...
an = a1 +d(n -1)
You are given a1 = 2, a12 = 211, so ...
211 = 2 + d(12 -1)
209/11 = d = 19 . . . . . solve the above equation for the common difference
Now, we can use the same equation to find n for an = 135.
135 = 2 + 19(n -1)
133/19 = n -1 . . . . . . . subtract 2, divide by 19
7 +1 = n = 8 . . . . . . . . add 1
135 is the 8th term of the sequence.
This essentially means 12-8
|| means absolute value which is the distance from 0 the number is
Basically it’s the number but positive
So the answer is 4
