Ask question

Ask question

All categories

3 years ago

12

Ethan wants to run 26.2 miles of the marathon in 4.5 hours. At about what rate will he have to run to reach his goal? Round to t

he nearest tenth.

1 answer:

ludmilkaskok [199]3 years ago

6 0

Answer: About 5.8 mph.

Step-by-step explanation: Divide 26.2 by 4.5 and it’ll give you 5.82222222... round to the nearest tenth and you get 5.8

You might be interested in

Help please?????? I’m confused

Rina8888 [55]

Answer:

$1000.00

Step-by-step explanation:

8 0

3 years ago

Explain how to simplify this expression: 4a + 19 - 3a - 7<br><br><br> WRITER

mafiozo [28]

Ok so put the a factors together first
4a + 19 - 3a - 7 = a + 19 + 7
a + 19 + 7 = a + 26

7 0

3 years ago

Read 2 more answers

F+ 20 = -1<br> Solve the equation and check your solution

Leona [35]

Answer:

f=-21

Step-by-step explanation:

-21+20=-1

f has to be a negative number as the answer is negative and -21 is the only plug in that would make sence as the answer is negative one.

6 0

3 years ago

12 + x/4 = 9<br> Simplify Plz need ASAP

agasfer [191]

Answer: X = -12

Step-by-step explanation: 1) 12 + x/4 = 9

2) 12 + x/ 2^2 = 9

3) x/ 2^2 + 12 = 9

6 0

3 years ago

1. What is the vertex form of the equation?

sergeinik [125]

1.vertex form is $y=a(x-h)^2+k$

to get into vertex form, complete the square

$y=-x^2+12x-4$

step 1: group x terms

$y=(-x^2+12x)-4$

step 2: factor coefient in front of x^2 term

$y=-1(x^2-12x)-4$

prep for next step: take 1/2 of linear (1st dgree term) and square it

$\frac{-12}{2}=-6$ , $(-6)^2=36$

step 3: add positive and negative of that previous number inside the parenthasees

$y=-1(x^2-12x+36-36)-4$

factor perfect squaer trionmial

$y=-1((x-6)^2-36)-4$

take out that -36 by expansion

$y=-1(x-6)^2+36-4$

$y=-1(x-6)^2+32$

2. factor out the 2

$2(x^2+8x+12)$

what 2 numbers multiply to get 12 and add to get 8?

2 and 6

$2(x+2)(x+6)$

3.

for $ax^2+bx+c=0$

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

in our case

$x^2-7x-6=0$

a=1, b=-7, c=-6

$x=\frac{-(-7) \pm \sqrt{(-7)^2-4(1)(-6)}}{2(1)}$

$x=\frac{7 \pm \sqrt{73}}{2}$

so $x=\frac{7+\sqrt{73}}{2}$ and $x=\frac{7-\sqrt{73}}{2}$

4. remember that $i=\sqrt{-1}$ so $i^2=-1$

treat $i$ as a variable

$(-2i)(8i)=$

$(-2)(i)(8)(i)=$

$(-2)(8)(i)(i)=$

$(-16)(i^2)=$

$(-16)(-1)=$

[tex}16[/tex]

8 0

3 years ago

Read 2 more answers