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Sedbober [7]
2 years ago
11

HELP meeeeeeeeee pwease :'( BRAINLIEST

Mathematics
2 answers:
Mazyrski [523]2 years ago
7 0
Vas happenin!!!

I think it’s C

Hope this helps

-Zayn Malik
denis23 [38]2 years ago
6 0

Answer:

<h2>Letter <u>C</u></h2><h3><u>D</u><u>o</u><u>m</u><u>a</u><u>i</u><u>n</u><u> </u><u>i</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>X</u></h3><h3><u>R</u><u>a</u><u>n</u><u>g</u><u>e</u><u> </u><u>i</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>Y</u></h3>

Step-by-step explanation:

hope it help

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Help ASAP show work please thanksss!!!!
Llana [10]

Answer:

\displaystyle log_\frac{1}{2}(64)=-6

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

log_b(1) = 0

Logarithm of the base:

log_b(b) = 1

Product rule:

log_b(xy) = log_b(x) + log_b(y)

Division rule:

\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)

Power rule:

log_b(x^n) = n\cdot log_b(x)

Change of base:

\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

\displaystyle log_\frac{1}{2}(64)

Factoring 64=2^6.

\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)

Since

\displaystyle 2=(1/2)^{-1}

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})

Applying the logarithm of the base:

\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}

5 0
2 years ago
Guys can you please to this thank
hram777 [196]
= 16 + 49 - 3(11)  - 4(10)
= 16 + 49 - 33 - 40
= -8
7 0
3 years ago
Solve each system using substitutions<br> Y+4=x<br> -2+ Y=8
klemol [59]
-2 + Y = 8
Y = 10
Plug in Y to the first equation, 10 + 4 = X
X = 14
3 0
3 years ago
Read 2 more answers
How many inches are there in 4.5 feet ?
Inessa [10]
54 inches

4.5 x 12 = 54
8 0
3 years ago
What is the value of X if 9^x^-^1-2=25?
nadezda [96]

Answer:

\frac{5}{2}

Step-by-step explanation:

First, add two to both sides to get 9^{x-1}=27

There are two ways to solve this from here

  1. Think about what power you would have to raise 9 to to get to 27. 9^{\frac{1}{2}} = 3 and 3^3=27. So, multiplying the powers (because it is a power to a power) you get 9^{\frac{3}{2}}=27. This means that x - 1 = \frac{3}{2} or x = \frac{5}{2}.
  2. Take the log of both sides.

This gives us \log_9(27)=x-1\\\log_9(27)+1=x\\\log_9(3^3)+1=x\\3\log_9(3)+1=x\\3(\frac{1}{2})+1=x\\\frac{3}{2}+1 = x\\\\\frac{5}{2} = x

4 0
3 years ago
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