Answer:
A) WZ
Step-by-step explanation:
B,C, and D, come before RU
Find m∠BOC, if m∠MOP = 110°.
Answer:
m∠BOC= 40 degrees
Step-by-step explanation:
A diagram has been drawn and attached below.
- OM bisects AOB into angles x and x respectively
- ON bisects ∠BOC into angles y and y respectively
- OP bisects ∠COD into angles z and z respectively.
Since ∠AOD is a straight line
x+x+y+y+z+z=180 degrees

We are given that:
m∠MOP = 110°.
From the diagram
∠MOP=x+2y+z
Therefore:
x+2y+z=110°.
Solving simultaneously by subtraction

x+2y+z=110°.
We obtain:
x+z=70°
Since we are required to find ∠BOC
∠BOC=2y
Therefore from x+2y+z=110° (since x+z=70°)
70+2y=110
2y=110-70
2y=40
Therefore:
m∠BOC= 40 degrees
Answer:
Make two piece of this figure
Step-by-step explanation:
then use formula of v = l × b × h
Answer:
See the attached figure.
Given:
u = (-3.5 , -1.5) and v = (-1.25 , 2.25)
So,
2v = 2 * (-1.25 , 2.25) = (-2.5, 4.5)
∴ 2v - u = (-2.5, 4.5) - (-3.5 , -1.5) = (1 , 6)
The graph of the vectors is as shown in the attached figure.
You jogged 2/3 of a mile. 1/3 plus 1/3 equals 2/3.