Question

The minimum takeoff speed for a certain airplane is 75 m/s. What minimum acceleration is required if the plane must leave a runway of length 1050 m? Assume the plane starts from rest at one end of the runway.

Answer 1

The solution is in the attachment

Answer 2

Answer:

a = 2.68 m/s^2

The minimum acceleration required is 2.68 m/s^2

Step-by-step explanation:

Using the equation of motion;

v^2 = u^2 + 2as .....1

Where,

v = final velocity

u = initial velocity

a = acceleration

s = displacement

From equation 1;

Making a the subject of formula.

a = (v^2 - u^2)/2s ....2

Given;

v = 75 m/s

u = 0 (it starts from rest)

s = 1050m

Substituting the given values into equation 2

a = (75^2 - 0)/(2×1050)

a = 2.68 m/s^2

The minimum acceleration required is 2.68 m/s^2