The minimum takeoff speed for a certain airplane is 75 m/s. What minimum acceleration is required if the plane must leave a runw
ay of length 1050 m? Assume the plane starts from rest at one end of the runway.
2 answers:
The solution is in the attachment
Answer:
a = 2.68 m/s^2
The minimum acceleration required is 2.68 m/s^2
Step-by-step explanation:
Using the equation of motion;
v^2 = u^2 + 2as .....1
Where,
v = final velocity
u = initial velocity
a = acceleration
s = displacement
From equation 1;
Making a the subject of formula.
a = (v^2 - u^2)/2s ....2
Given;
v = 75 m/s
u = 0 (it starts from rest)
s = 1050m
Substituting the given values into equation 2
a = (75^2 - 0)/(2×1050)
a = 2.68 m/s^2
The minimum acceleration required is 2.68 m/s^2
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