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MAVERICK [17]
2 years ago
14

A line contains the points R (-1, 8) S (1, 4) and T (6, y). Solve for y. Be sure to show and explain all work.

Mathematics
1 answer:
Nikitich [7]2 years ago
3 0

Given:

A line contains the points R(-1, 8), S(1, 4) and T(6, y).

To find:

The value of y.

Solution:

Three points are collinear if:

x_1(y_2-y_3)+x_2(y_3-y_2)+x_3(y_1-y_2)=0

A line contains the points R(-1, 8), S(1, 4) and T(6, y). It means, these points are collinear.

-1(4-y)+1(y-8)+6(8-4)=0

-4+y+y-8+48-24=0

2y+12=0

Subtract 12 from both sides.

2y=-12

Divide both sides by 2.

y=\dfrac{-12}{2}

y=-6

Therefore, the value of y is -6.

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\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
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25=t^2\implies \boxed{5=t}


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