All categories

4 years ago

What is the measure of Angle y?

Mathematics

2 answers:

olga55 [171]4 years ago

7 0

Answer:

Step-by-step explanation:

180 - 139 = 41

____ [38]4 years ago

3 0

Answer: A: 41

Step-by-step explanation: The answer is a because the line equaled 180 degrees. So when the measurement of 139 is shown then you would subtract 139 from 180, and your sum is 41.

You might be interested in

Jodi owns 112 shares of stock selling for $16.20. How many more shares can she purchase after receiving a dividend of $0.80 per

loris [4]

Answer:

5 shares if only whole shares are allowed

5.53 shares if fractional shares are allowed

Step-by-step explanation:

112(0.80) / 16.20 = 5.530864

8 0

4 years ago

How much does the cherry vanilla ice cream cost per quart? (1.75 quarts costs $4)

alina1380 [7]

Answer:2.28571429 dollars. 4/1.75= 2.28571429, therefore showing how much one will cost.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

NEED HELP FAST!!!

Lostsunrise [7]

(used with a singular verb) the systematic treatment of magnitude,relationships between figures and forms, and relations betweenquantities expressed symbolically

3 0

3 years ago

Verify that:

Lelu [443]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to verify that:

$\displaystyle \left(\cos(x)\right)\left(\cot(x)\right)=\csc(x)-\sin(x)$

Note that cot(x) = cos(x) / sin(x). Hence:

$\displaystyle \left(\cos(x)\right)\left(\frac{\cos(x)}{\sin(x)}\right)=\csc(x)-\sin(x)$

Multiply:

$\displaystyle \frac{\cos^2(x)}{\sin(x)}=\csc(x)-\sin(x)$

Recall that Pythagorean Identity: sin²(x) + cos²(x) = 1 or cos²(x) = 1 - sin²(x). Substitute:

$\displaystyle \frac{1-\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)$

Split:

$\displaystyle \frac{1}{\sin(x)}-\frac{\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)$

Simplify:

$\csc(x)-\sin(x)=\csc(x)-\sin(x)$

Problem 2)

We want to verify that:

$\displaystyle (\csc(x)-\cot(x))^2=\frac{1-\cos(x)}{1+\cos(x)}$

Square:

$\displaystyle \csc^2(x)-2\csc(x)\cot(x)+\cot^2(x)=\frac{1-\cos(x)}{1+\cos(x)}$

Convert csc(x) to 1 / sin(x) and cot(x) to cos(x) / sin(x). Thus:

$\displaystyle \frac{1}{\sin^2(x)}-\frac{2\cos(x)}{\sin^2(x)}+\frac{\cos^2(x)}{\sin^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}$

Factor out the sin²(x) from the denominator:

$\displaystyle \frac{1}{\sin^2(x)}\left(1-2\cos(x)+\cos^2(x)\right)=\frac{1-\cos(x)}{1+\cos(x)}$

Factor (perfect square trinomial):

$\displaystyle \frac{1}{\sin^2(x)}\left((\cos(x)-1)^2\right)=\frac{1-\cos(x)}{1+\cos(x)}$

Using the Pythagorean Identity, we know that sin²(x) = 1 - cos²(x). Hence:

$\displaystyle \frac{(\cos(x)-1)^2}{1-\cos^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}$

Factor (difference of two squares):

$\displaystyle \frac{(\cos(x)-1)^2}{(1-\cos(x))(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}$

Factor out a negative from the first factor in the denominator:

$\displaystyle \frac{(\cos(x)-1)^2}{-(\cos(x)-1)(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}$

Cancel:

$\displaystyle \frac{\cos(x)-1}{-(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}$

Distribute the negative into the numerator. Therefore:

$\displaystyle \frac{1-\cos(x)}{1+\cos(x)}=\displaystyle \frac{1-\cos(x)}{1+\cos(x)}$

3 0

3 years ago

Describe two different cross section shapes that can be formed by slicing a cylinder. For each shape describe how the cross sect

artcher [175]

either a rectangle or circle will be made. If you cut it horizontially you will get a circle. Vertically and you will have a rectangle

5 0

3 years ago