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2 years ago

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Please someone help!!! The sides of the base of a square right prism are 16 cm each and the height of the prism is 10 cm. what i

s the surface area of this prism?

1 answer:

LuckyWell [14K]2 years ago

3 0

The surface area is 1152 cm^2

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Find the volume of the figure. Round to the nearest tenth if necessary.<br> 3 yd<br> 3 yd<br> 10 yd

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The graph of F(x) shown below has the same shape as the graph of G(x) = x^2 but it is shifted down 5 units and to the left 4 uni

grandymaker [24]

$\bf ~\hspace{10em}\textit{function transformations} \\\\\\ \begin{array}{llll} f(x)= A( Bx+ C)^2+ D \\\\ f(x)= A\sqrt{ Bx+ C}+ D \\\\ f(x)= A(\mathbb{R})^{ Bx+ C}+ D \end{array}\qquad \qquad \begin{array}{llll} f(x)=\cfrac{1}{A(Bx+C)}+D \\\\\\ f(x)= A sin\left( B x+ C \right)+ D \end{array} \\\\[-0.35em] ~\dotfill\\\\ \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\ \bullet \textit{ flips it upside-down if } A\textit{ is negative}\\ ~~~~~~\textit{reflection over the x-axis}$

$\bf \bullet \textit{ flips it sideways if } B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis} \\\\ \bullet \textit{ horizontal shift by }\frac{ C}{ B}\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}\\\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by } D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{ B}$

with that template in mind, let's see

down by 5 units, D = -5

to the left by 4 units, C = +4

$\bf G(x)=x^2\implies G(x)=1(1x+\stackrel{C}{0})^2+\stackrel{D}{0} \\\\\\ \begin{cases} D=-5\\ C=+4 \end{cases}\implies F(x)=1(1x+\stackrel{C}{4})^2\stackrel{D}{-5}\implies F(x)=(x+4)^2-5$

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2 years ago

a storage jug was 4/5 full of water when did get indicated 72 what was the full capacity of the storage jug

IRISSAK [1]

Answer:

<em><u>9</u></em><em><u>0</u></em><em><u>. </u></em><em><u>(</u></em><em><u> </u></em><em><u>was </u></em><em><u>the </u></em><em><u>full </u></em><em><u>capacity</u></em><em><u> of</u></em><em><u> </u></em><em><u>jug</u></em><em><u>)</u></em>

<em><u>to </u></em><em><u>solve </u></em><em><u>this</u></em><em><u> </u></em>

<em><u>firstly</u></em><em><u> </u></em><em><u>let </u></em><em><u>the </u></em><em><u>full </u></em><em><u>capacity</u></em><em><u> </u></em><em><u>of </u></em><em><u>jug </u></em><em><u> </u></em>

<em><u> </u></em><em><u> </u></em>

<em><u>be</u></em><em><u>. </u></em><em><u>x</u></em>

<em><u>so,</u></em><em><u> </u></em>

<em><u>4</u></em><em><u>/</u></em><em><u>5</u></em><em><u>*</u></em><em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u>2</u></em>

<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u>2</u></em><em><u>*</u></em><em><u>5</u></em><em><u>/</u></em><em><u>4</u></em>

<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>9</u></em><em><u>0</u></em>

<em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em>

6 0

2 years ago