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mihalych1998 [28]
3 years ago
14

Two 6 sided dice are rolled. what is the probability of rolling a 3 on either of the dice

Mathematics
1 answer:
emmasim [6.3K]3 years ago
7 0
There is a 2 of 6 percent chance that one them might land on three if you add one extra dice it would be 3 of 6 percent chance and so on.

Hope this Helped!

;D
Brainliest??
You might be interested in
The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.
mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

-----------

For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.96516 probability of a chipmunk living through the year, thus p = 0.96516

Item a:

  • Two is P(X = 2) when n = 2, thus:

P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

  • Six is P(X = 6) when n = 6, then:

P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

  • At least one not living is:

P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0
3 years ago
HELP ME PLEASE IM DUMB
m_a_m_a [10]

Answer:

-17/12

Step-by-step explanation:

-(2/3)-(3/4)

-(8/12)-(9/12)

-17/12

6 0
3 years ago
Which numbers will produce a rational number when multiplied by 1/5
labwork [276]
A rational number times a rational number=rational numberan irrational number times a rational number=irrational number
remember, a rational number is a number that can be written as a/b where a and b are integers and b≠0


A is irrational because the pattern doesn't repeatb is irrational because it's a crazy square rootC is irrationalD is not irrational, it is a fraction 

answer is D

 
3 0
3 years ago
Is 8,2,1/2,1/8 exponential or not
Anvisha [2.4K]

Answer:

not

Step-by-step explanation:

6 0
2 years ago
A pole-vaulter uses a 15-foot-long pile. She grips the pole so that the segment below her left hand is twice the length of the s
Shalnov [3]
Let x + 1.5 be length of segment above left hand
Let 2x be length of segment below left hand

15 = x + 1.5 + 2x
15 = 3x + 1.5
15 - 1.5 = 3x
13.5 = 3x
13.5/3= 3x/3 
4.5 = x
x = 4.5
This is the length above the left hand. 

2x must be then 4.5*2 = 9 foot
This is the length below the left hand. 

Checking
4.5 + 9 + 1.5 = 15 foot 

Adding length below left hand & length of left hand to right hand:
9 + 1.5 = 10.5
The right hand is hence 10.5 foot far up the pole.
6 0
3 years ago
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