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Aleks04 [339]
3 years ago
12

Need answer pleaseeeee

Mathematics
2 answers:
Afina-wow [57]3 years ago
4 0
C 150cm is the volume
geniusboy [140]3 years ago
4 0

Answer:

150cm3

Step-by-step explanation:

multiply all the numbers together and the three stands for the total number of cm were added.

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12, 21, 30 and 39 are the first four terms in a sequence
vivado [14]

Answer:

12, 21, 30, 39, 48, 57, 66, 75, 84.  

Ninth term is 84.

Step-by-step explanation:

The rule for this sequence is "add 9".

So, using this rule, we can do......

12, 21, 30, 39, 48, 57, 66, 75, 84.

<em>Remember to add 9 each time!</em>

Best of luck :3

4 0
2 years ago
Is 3√75 less than, greater than, or equal to 7√27
posledela
Greater than (I'm like 80% sure of my answer)
8 0
3 years ago
Read 2 more answers
!lol help pls im vv bad at math and angles
Vanyuwa [196]

Answer:

y=130°

Step-by-step explanation:

180-(90+40)

180-130

50°

y=180°-50°

=130°

6 0
3 years ago
Doreen bought a cell phone for x dollars. One year later the value of the phone was 0.75x. Which expression is another way to de
OLEGan [10]

3/4x

0.75=75/100     =3/4

   75:25=3

100:25=4

6 0
3 years ago
Use the Fundamental Theorem for Line Integrals to find Z C y cos(xy)dx + (x cos(xy) − zeyz)dy − yeyzdz, where C is the curve giv
Harrizon [31]

Answer:

The Line integral is π/2.

Step-by-step explanation:

We have to find a funtion f such that its gradient is (ycos(xy), x(cos(xy)-ze^(yz), -ye^(yz)). In other words:

f_x = ycos(xy)

f_y = xcos(xy) - ze^{yz}

f_z = -ye^{yz}

we can find the value of f using integration over each separate, variable. For example, if we integrate ycos(x,y) over the x variable (assuming y and z as constants), we should obtain any function like f plus a function h(y,z). We will use the substitution method. We call u(x) = xy. The derivate of u (in respect to x) is y, hence

\int{ycos(xy)} \, dx = \int cos(u) \, du = sen(u) + C = sen(xy) + C(y,z)  

(Remember that c is treated like a constant just for the x-variable).

This means that f(x,y,z) = sen(x,y)+C(y,z). The derivate of f respect to the y-variable is xcos(xy) + d/dy (C(y,z)) = xcos(x,y) - ye^{yz}. Then, the derivate of C respect to y is -ze^{yz}. To obtain C, we can integrate that expression over the y-variable using again the substitution method, this time calling u(y) = yz, and du = zdy.

\int {-ye^{yz}} \, dy = \int {-e^{u} \, dy} = -e^u +K = -e^{yz} + K(z)

Where, again, the constant of integration depends on Z.

As a result,

f(x,y,z) = cos(xy) - e^{yz} + K(z)

if we derivate f over z, we obtain

f_z(x,y,z) = -ye^{yz} + d/dz K(z)

That should be equal to -ye^(yz), hence the derivate of K(z) is 0 and, as a consecuence, K can be any constant. We can take K = 0. We obtain, therefore, that f(x,y,z) = cos(xy) - e^(yz)

The endpoints of the curve are r(0) = (0,0,1) and r(1) = (1,π/2,0). FOr the Fundamental Theorem for Line integrals, the integral of the gradient of f over C is f(c(1)) - f(c(0)) = f((0,0,1)) - f((1,π/2,0)) = (cos(0)-0e^(0))-(cos(π/2)-π/2e⁰) = 0-(-π/2) = π/2.

3 0
3 years ago
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