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tangare [24]
2 years ago
11

A packet of crisps contains 50g. If a “new size” packets contain 15% more, how many grams of crisps are in the “new size” packet

s?
Plz help
Mathematics
1 answer:
Agata [3.3K]2 years ago
4 0
To solve this, you’d multiply 50 by 1.15 to get 57.5 grams of crisps.
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Irina18 [472]
There isn’t an answer because you haven’t provided us enough data
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What is mZ1?<br> 490<br> 470<br> m21
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490

Step-by-step explanation:

4333333

67

8

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PLEASE GIVE AN EXPLANATION WITH YOUR ANSWER! The table below shows the change in the value of shares over the last three years.
gulaghasi [49]

First, lets convert them into multipliers:

The multiplier for a:

                             25% increase = 1.25

                             40% decrease = 0.6

                             40% increase  = 1.4

Now to work out the overall percentage change, we just times all of the multipliers together, and convert it back to a percentage:

1.25 x 0.6 x 1.4 = 1.05    

So the overall multiplier is 1.05

And a multiplier of 1.05 = a <u>5% increase</u>.

That means that the percentage change is + 5%

_________________________________________

Answer:

The percentage change in shares from the start of 2013 to the end of 2015 is:

+ 5%

_______________________________________

Note: if you haven't been taught multipliers - then ask and I'll try my best to explain!

6 0
3 years ago
Try to figure out this riddle : An eight-digit number contains two 1's, two 2's, two 3's, and two 4's. The 1's are separated by
lord [1]
It should be 23421314
6 0
3 years ago
The perimeter of the rectangle is 22 meters, and the perimeter of the triangle is 12 meters. Find the dimensions of the rectangl
lianna [129]

Answer:

Length:8 m

Width:3 m

Step-by-step explanation:

<u><em>The complete question is</em></u>

If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.

step 1

<em>Perimeter of rectangle</em>

we know that

The perimeter of rectangle is equal to

P=2(L+W)

we have

P=22\ m

so

22=2(L+W)

Simplify

11=L+W -----> equation A

step 2

Perimeter of triangle

The perimeter of triangle is equal to

P=\frac{L}{2}+W+5

P=12\ m

so

12=\frac{L}{2}+W+5

Multiply by 2 both sides

24=L+2W+10

L+2W=14 ----> equation B

Solve the system of equations by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (8,3)

see the attached figure

therefore

The dimensions of the rectangle are

Length:8 m

Width:3 m

3 0
3 years ago
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