14-63=49 and 49+14=63 so x=49.
Hope this helps :)
Hi there! The answer is 44.
To find our answer we have to multiply 55 by 4/5. Then we get the following:

Therefore, 44 of Matthew's pitches were strikes.
Answer:
sorry I don't remember bye I will try to remember
Answer:
(a)
Step-by-step explanation:
(a)The degree of a polynomial is the highest power of the unknown variable in the polynomial.
A polynomial is said to be in standard form when it is arranged in descending order/powers of x.
An example of a fourth degree polynomial is: 
We know the polynomial above is in standard form because it is arranged in such a way that the powers of x keeps decreasing.
(b)Polynomials are closed with respect to addition and subtraction. This is as a result of the fact that the powers do not change. Only the coefficients
change. This is illustrated by the two examples below:

The degrees do not change in the above operations. Only the number beside each variable changes. Therefore, the addition and subtraction of polynomials is closed.
1. a) equation of the line :
y - intercept = -7
so, it will pass through point (0, -7)
and if we plug the value of x as 5, we get
so, it will pass through point (5, -5) too
now, just plot the points (0 , -7) and (5 , -5) and join them.
2. b) equation of line is :
here, y - intercept = 5
so the line passes through point (0 , 5)
now, Plugging the value of x = 1 we get :
so, the given line passes through point (1 , 2)
plotting the points, we can get our required line.