Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
Yes they are , since they are very common in ones body
-2x^2(4x − 3)
=-8x^3 + 6x^2
hope it helps
Answer:
38.4
Step-by-step explanation:
48*20%=9.6 48-9.6=38.4
Answer:
50%
Step-by-step explanation:
not even = 2 nums
pnoteven = 2 ÷ 4 × 100
