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3 years ago

HELP! i’ll mark you as brainliest

Mathematics

2 answers:

Nadya [2.5K]3 years ago

7 0

Answer:

m<F = 79 degrees

Step-by-step explanation:

As per the given information;

m<E = 22, the triangle EDF (the one that is given in the picture) is isosceles (meaning that the sides are congruent).

In an isosceles triangle, (a triangle where the sides are congruent) the base angles (the angles opposite to the two congruent sides) are also congruent. One should also know, that in an isosceles triangle, like in any triangle, the sum of the measures of the angles equals 180 degrees.

Using this we can say that

m<D = m<F

To keep it simple while solving the problem, let's say that they have a value of x degrees.

So,

m<E + m<D + m<F =180

Subsitute

22 + x + x = 180

Simplify and inverse operations

22 + x + x = 180

-22 -22

2x = 158

/2 /2

x = 79

So the measure of <D and <F is 79 degrees.

Gala2k [10]3 years ago

6 0

Answer:

Step-by-step explanation:

An acute triangle adds up to 180

subtract 22 from 180

180-22 = 158

divide by 2

158/2 = 79

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3 years ago

What is 5X minus Y equals six minus 2X plus Y equals eight

34kurt

Answer:

x = 8/3, y = 22/3

Step-by-step explanation:

5x-y=6-2x+y=8

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3 years ago

Pls help! evaluate f(4) on this table

Kruka [31]

Answer:

Step-by-step explanation:

f(4) just means use 4 for x. The table has all the x's across the top (sometimes they are in columns instead) The f(x) in the second row is the output that goes with each x. When x is 4, the f(x) is 37.

All is one math sentence:

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7 0

2 years ago

A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar

ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let $\mu$ = mean waiting time for bus number 14.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 10 minutes {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, $H_A$ : $\mu$ < 10 minutes {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean waiting time = 7.8 minutes

s = sample standard deviation = 2.5 minutes

n = sample of different occasions = 18

So, test statistics = $\frac{7.8-10}{\frac{2.5}{\sqrt{18} } }$ ~ $t_1_7$

= -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

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4 years ago

I need help in part A and part B

mezya [45]

One thing to remember about percent is that "%" means the same as "/100".

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8 0

4 years ago