Let the larger number be w and the smaller number be k;
5w-11=3k
3k+16=4w
Reorganizing the equations;
5w-3k=11
4w-3k=16
Subtracting equation 2 from equation 1:
w=-5
Replacing value of w in equation 1;
5(-5)-11=3k
-25-11=3k
3k=-36
k=-12
The numbers are -5 and -12
the first 4 would be rounded up tot he nearest dollar and the last one rounded down to the nearest dollar
doing that I estimate $23.00
Answer is C
Answer:
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- <u>Yes, she has enough water.</u>
Explanation:
To <em>estimate</em> the value, you can work with friendly numbers: numbers closed to the given numbers and with which you can perform easy mental calculations.
For example 4.55 may be rouned to 5, 4.85 may be rounded to 5, and 3.25 may be rounded to 3. That yields 5 + 5 + 3 = 13
Then, it seems you have about 13 liters. Is the final number equal or greater than 12 for sure?
To round 4.55 to 5 you increased the amount in 0.45, to round 4.85 to 5 you increased the amount by 0.15, and to round 3.25 to 3 you decreased the amount in 0.25.
What was the net change in your values: 0.45 + 0.15 - 0.25 = 0.60 - 0.25 = 0.35. Those are easy calculations that you can perform in your mind.
That means that you increased your total in less than 1 liter. Meaning that the final total is overestimated by 0.35, and that if you used the real amounts to make the calculations, the total will be still more than 12.
.08 cents per ounce, because 2.40 ÷30 =.08
<h2>
Explanation:</h2><h2>
</h2>
The diagram is missing but I'll assume that the arc BDC is:
And another arc, let's call it FGH. measures:
If those arc are equal, then this equation is true:
Substituting k into the first equation:
