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3 years ago

What is the distance between (2,3) and (5,7)

Mathematics

1 answer:

valentinak56 [21]3 years ago

4 0

This is the rule for any calculation of this type. Note that you can replace X(B) by X(A) and the same for Y because the answers are squared and you'll always get the same value

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40÷ 1/25

Lubov Fominskaja [6]

#1. 1000
#2. 1/45 (decimal is .02 with the line above the two
#3. 32/9
#4. 1/20 (decimal form .05
#5. 4
#6. 47/4 (decimal is 11.75)
#7. 1/4 (decimal 0.25
#8. 1/2 decimal is 0.5
#9. 45
#10. 12

I really hope this help

8 0

3 years ago

Write a TRUE statement using the words acute angle and regular octagan.<br><br> THANK YOU!!

marishachu [46]

In a regular octagon it is impossible to have an acute angle!
Hope this helps!!

3 0

3 years ago

Read 2 more answers

If f(x)= x-3 over x and g(x)= 5x-4 what is the domain of (f•g)(x)

marusya05 [52]

Answer:

I attached the work to your problem below.

I hope it helps.

8 0

3 years ago

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

<u>I will try to give as many details as possible. </u>

First of all, I just would like to say:

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Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! （＊＾Ｕ＾）人（≧Ｖ≦＊）/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

3 years ago

The linear regression line for Tampa Tribune Database is y=8x+367. In approximately what year is the Tampa Tribune expecting to

lakkis [162]

The Tampa Tribune expecting to add 700 new pictures per year to their database in 2041

<h3>The linear equation of the graph</h3>

The equation of the line of best fit is given as:

$y = 8x + 367$

When the number of pictures added is 700, we have:

y = 700

Substitute 700 for y in $y = 8x + 367$

$700 = 8x + 367$

Subtract 367 from both sides of the equation

$333= 8x$

Rewrite the above equation as:

$8x = 333$

Divide both sides by 8

$x = 41.625$

Remove decimal (do not approximate)

$x = 41$

This means that:

$Year = 2000 +41$

$Year = 2041$

Hence, the Tampa Tribune expecting to add 700 new pictures per year to their database in 2041

Read more about linear regression at:

brainly.com/question/26137159

8 0

3 years ago