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2 years ago

Complete the fraction that is equivalent to . = ¯¯¯¯¯ 24

Mathematics

1 answer:

wariber [46]2 years ago

4 0

Answer:

24 is equivalent to 24/1

Step-by-step explanation: Hope this helped you feel free to ask questions in comments.

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100e^0.125t=200 A. t= ln(16) B. t= ln(256) C. t= 8ln(100) D. t= 0.08ln(200)

Drupady [299]

The correct answer is C. t= 8ln(100)

Hope this helped! :)

^-^

5 0

3 years ago

Evaluate 8-m/n +m when m=8 and n=2

RUDIKE [14]

Substitute the answer: therefore, 8-8/2+8= 0/10 in fraction form, but as you feather simplify 0 divide by 10 you'll get the answer as 0.

3 0

3 years ago

Tickets at the carnival cost 35 each.on Friday night the carnivals earned a total of 12,425 in ticket sales on Saturday night th

Blababa [14]

ticket sale on Saturday night is triple the ticket sale on Friday night.

Therefore

ticket sales on Saturday night = 3 x 12425 = 37275

Then

ticket sales for both nights = 12425 + 37275 = 49700

A ticket costs 35.

Let the number of people that attended the carnival on both nights be n.

Then, we have

$\begin{gathered} 35n=49700 \\ \Rightarrow n=\frac{49700}{35}=1420 \end{gathered}$

Therefore 1420 people attended the carnival on both nights

6 0

7 months ago

What is 5 13.5% of ?

Alekssandra [29.7K]

Answer:

67.5

Step-by-step explanation:

Okay so I spent way to long overthinking this problem but in the end, I just used common sense to figure this one out. *it still may be wrong though...

A way to check if this is correct is dividing 67.5 by 5 and it equals to 13.5 which should make that answer correct?

4 0

3 years ago

Read 2 more answers

The population of rabbits on an island is growing exponentially. In the year 1994, the population of rabbits was 9600, and by 20

drek231 [11]

Answer:

49243

Step-by-step explanation:

Given that the population of rabbits on an island is growing exponentially.

Let the population, $P=P_0e^{bt}$

where, $P_0$ and b are constants, t=(Current year -1994) is the time in years from 1994.

In 1994, t=0, the population of rabbit, P=9600, so

$9600=P_0e^{b\times 0}$

So, $P_0=9600$

and in 2000, t=2000-1994=6 years and population of the rabbit, P=18400

$18400=9600 \times e^{b\times 6} \\\\\frac{18400}{9600}=e^{b\times 6} \\\\$

$\ln(23/12}=6b \\\\$

$b = \frac{\ln{1.92}}{6} \\\\$

b=0.109

On putting the value of P_0 and b, the population of the rabbit after t years from 1994 is

$P=9600 \times e^{0.109\times t}$

In 2009, t= 2009-1994=15 years,

So, the population of the rabbit in 2009

$P=9600 \times e^{0.109\times 15}=49243$

Hence, the population of the rabbit in 2009 is 49243.

7 0

3 years ago