Question

7. Write an equation of the line that passes through points (3, 7) and (5, 11).

Answer 1

(3, 7) and (5, 11)   We first will determine the slope:

Slope (or "m") = (11 - 7) / (5 -3) = 4 / 2 = 2

The equation can be written as y = mx +b (OR b = y - mx) and we'll calculate "b" by using one of the given points (3, 7) ;; b = 7 -2*3   b = 1

So, the equation is: y = 2*x + 1

 

Answer 2

Answer:

$y=2x+1$

Step-by-step explanation:

We are asked to write an equation of that line that passes through points (3, 7) and (5, 11).

First of all, we will find slope of our given line using the coordinates of given points as:

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{11-7}{5-3}$

$m=\frac{4}{2}$

$m=2$

Now, we will write our given equation in slope-intercept form $y=mx+b$, where m represents slope and b represents y-intercept.

Let us find the y-intercept using coordinates of point (3,7) and slope as:

$7=2*3+b$

$7=6+b$

$7-6=6-6+b$

$1=b$

Therefore, our required equation in slope-intercept form would be $y=2x+1$.