Hello!
The graph y < -2/3x + 2 has a dotted line. That means that any points on the dotted line or not shaded, is not a solution to this inequality. Since we are given 4 choices, we can substitute those values into the given inequality to see if it is true.
A) (0, 2)
2 < -2/3(0) + 2
2 < 2, this is false.
B) (3, 0)
0 < -2/3(3) + 2
0 < -2 + 2
0 < 0, this is false.
C) (0, 0)
0 < -2/3(0) + 2
0 < 2, this is true.
D). (0, 3)
3 < -2/3(0) + 2
3 < 2, this is false.
To check if choice C) (0, 0) is true, we should look at the given graph.
Since (0, 0) is in the shaded area, and is not graphed on the dotted line, therefore, a solution to this linear inequality is C, (0, 0).
Answer:
Step-by-step explanation:
Let 
and 
. Now we evaluate the given function at 
:
(1)
Which means that 
is less than the y-component of A. Therefore, the right answer is .
Given the following values for a quadratic function, which is the graph of the function? (–1, 0), (0, 3), (1, 4), (2, 3), (3, 0)
Firdavs [7]
Answer:
The function of the graph is f(x) = - x² + 2x + 3
Step-by-step explanation:
Using the value of the graph we can say that the the function is negative x² because there are x-intercepts and the y-intercept if above 0.
Using the x-intercepts we can form the function of the graph:
-(x + 1)(x - 3) - we have a negative in front of the two brackets because the function is a negative. Now we multiply out the brackets and the negative at the end:
-(x² - 2x - 3)
- x² + 2x + 3 - So the function of the graph is:
f(x) = - x² + 2x + 3
I think that would be the Chytridiomycota fungi
Of the four x-coordinates to choose only 1/√(11) belongs can belong to the unit circle.
The other three x-coordinates are greater than 1, then they are out of the unit circle.
The unit circle formula is x^2 +y^2 = 1
Then to find the y-coordinate given the x-coordinate you can solve for y from that formula:
y^2 = 1 - x^2
y = (+/-)√(1-x^2)
Substitute the value of x
y = (+/-)√{1 - [1/√(11)]^2} = (+/-) √{(1 - 1/11} =(+/-) √ {(11 -1)/11 =(+/-)√(10/11) ≈ +/- 0.95
