Answer:
43. I'm not really sure about this one but here's what I got:
The average height of a 4th grader is 58 inches. (Maybe that'll help) Also if it's by the number of kids in the class....I would assume that there are at most 33 kids in the class....I'm not sure what it's asking...sorry :(
46. There are 8 total marbles so if you were selecting a green marble the probability of getting a green marble would be 3/8. If there are 2 blue marbles then the probability would be 2/8 or 1/4
LINK: https://mathbitsnotebook.com/Geometry/Probability/PBIndependentDependent.html
48. In a deck of cards there are 26 black cards and 26 red cards. Number of event occurrences. Total number of trials. For example, if a dice is rolled 6000 times and the number '5' occurs 990 times, then the experimental probability that '5' shows up on the dice is 990/6000 = 0.165. That should help with this one
LINK:
https://explorable.com/experimental-probability
49. Since there are 6 sides and each side is a number 1-6, the probability of rolling a six is 1:6
50. This one is easy if you read the question right. There are no pink marbles....
I'm not that great with graphs
I hope this helped a little....some of the questions I didn't understand.
Answer:
B
Step-by-step explanation:
For a relationship to be a function
Each value of x in the domain can only have 1 unique value of y in the range. That is, one-to-one correspondence.
The only relation which meets this criteria is B
X = 352.3 [your work is correct]
then the perimeter would be 352.3 + 352.3 + 280 + 280 = 1,264.55
Answer:
(64,86.5)
Step-by-step explanation:
find the case where he gets 70 and the case where he gets 79
if his average is 70:
(75+62+85+2x)/5=70
(222+2x)/5=70
222+2x=350
2x=128
x=64
if his average is 79:
(75+62+85+2x)/5=79
(222+2x)/5=79
222+2x=395
222+2x=395
2x=173
x=86.5
(a) there are 8C2 = 28 ways of picking 2 girls from 8
And there are 21C4 = 5985 ways of picking 4 boys
Required number of ways for 2g / 4b = 28 * 5985 = 167,580
(b) at least 2 girls means combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or
6 girls.
2g/4b = 167,580 ways
3g/3b = 8C3 * 21C3 = 56 * 1330 = 74,480
4g/2b = 8C4* 21C2 = 70 * 210 = 14,700
5g 1b = 8C5* 21 = 56*21 = 1176
6 girls = 8C6 = 28
adding these up we get the answer to (b) which is 257,964
