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andreyandreev [35.5K]
3 years ago
6

Given the pre-image point A (4,-9) and it's image point A' (12, -27), determine the scale factor

Mathematics
1 answer:
WARRIOR [948]3 years ago
8 0

Answer:

scale factor = 3

Step-by-step explanation:

To determine the scale factor, calculate the ratio of the image x and y coordinates to the original x and y coordinates, that is

scale factor = \frac{12}{4} = \frac{-27}{-9} = 3

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GIVING EVERYTHING IF CORRECT. NO fake answers, you will be reported. And it hurts my grades so please don't.
seropon [69]

Answer:

A. 9.8 ft

Step-by-step explanation:

first convert the degrees to radians:

80° x (pi/180) ≈ 1.396

arc length = r x θ (always in radians)

= 7 x 1.396

= 9.772 ≈ 9.8 ft

3 0
2 years ago
Which system has the same situation below?
Likurg_2 [28]

Answer:

2

Step-by-step explanation:

Let's solve the given system of equations.

<u>Given system</u>

x +3y= 10 ----(1)

-2x -2y= 4 ----(2)

From (2):

-2(x +y)= 4

Dividing both sides by -2:

x +y= -2 ----(2)

Thus, options 3 and 4 are incorrect as x +y≠ -2.

(1) -(2):

(x +3y) -(x +y)= 10 -(-2)

Expand:

x +3y -x -y= 10 +2

2y= 12

Divide both sides by 2:

y= 12 ÷2

y= 6

Substitute y= 6 into (2):

x +6= -2

x= -6 -2

x= -8

Options (1) and (2) differs only by the value of the expression of -x +y. Thus, let's find its value in the given system of equations.

-x +y

= -(-8) +6

= 8 +6

= 14

Thus, option 2 is the correct option.

7 0
2 years ago
28 prime factorization
sineoko [7]

Answer:

2 x 2 x 7, or 2^2 x 7

Step-by-step explanation:

Let us use prime factorization to find the prime numbers that make up 28:

28 = 2 x 14            

2 is a prime number, 14 is not, so we have our first prime, 2.

14 = 2 x 7      

We then further break the number down into two prime numbers, 2 and 7. Since 2 and 7 are prime and we can't break them down any further our answer is 2 x 2 x 7, or 2^2 x 7.

3 0
3 years ago
Simplify (x^2)^3*5x/6x^2*15x^3
nasty-shy [4]

When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2

<h3>Data obtained from the question</h3>
  • [(x^2)^3 × 5x] / [6x^2 × 15x^3]
  • Simplification =?

<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>

[(x^2)^3 × 5x] / [6x^2 × 15x^3]

Recall

(M^a)^b = M^ab

Thus,

(x^2)^3 = x^6

  • [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]

Recall

M^a × M^b = M^(a+b)

Thus,

x^6 × 5x = 5x^(6 + 1) = 5x^7

6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5

  • [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5

Recall

M^a ÷ M^b = M^(a - b)

Thus,

5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2

Therefore,

  • [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2

Learn more about algebra:

brainly.com/question/2768008

#SPJ1

8 0
1 year ago
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