Given:
![f(x)=\sqrt[]{5x^2-2}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B%5D%7B5x%5E2-2%7D)
f(X) will be differentiated by chain rule.
![\begin{gathered} f^{\prime}(x)=\frac{1}{2\sqrt[]{5x^2-2}}\lbrack5(2x)\rbrack \\ f^{\prime}(x)=\frac{5x}{\sqrt[]{5x^2-2}} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20f%5E%7B%5Cprime%7D%28x%29%3D%5Cfrac%7B1%7D%7B2%5Csqrt%5B%5D%7B5x%5E2-2%7D%7D%5Clbrack5%282x%29%5Crbrack%20%5C%5C%20f%5E%7B%5Cprime%7D%28x%29%3D%5Cfrac%7B5x%7D%7B%5Csqrt%5B%5D%7B5x%5E2-2%7D%7D%20%5Cend%7Bgathered%7D)
Answer:
80 mm
Step-by-step explanation:
Pythagorean theorm can be applied here to solve for the length of the last leg, 
+ 
= 
, where (a) and (b) are the legs of the triangle and (c) is the hypotenuse. We can rearrange the pythagorean theorm for our purposes like the following:
b = √c^2 - √a^2
= √(82)^2 - √(18)^2
= √6724 - √324
= √6400
= 80 mm
Answer:
1
Step-by-step explanation:
3+2-(6-(1+1)
3+2-(6-2)
3+2-4
1
Answer:
1
Step-by-step explanation:
(-6,4) and (2,12)
slope = m = (y2 - y1) / (x2 - x1)
= 12 - 4 / 2 - (-6)
= 8/8
= 1
You have a base that is 8x8 and the slant height of the triangle is 22.
This is the formula, L=1/2Ph
H = 22 Meters
1. P=2L+2W -> 2(8)+2(8) = 32 meters
2. L= 1/2(32)(22) = 352 meters squared :)
