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aksik [14]
3 years ago
7

Solve the equation with a variable term on both sides: 5.1y+21.3=-0.3y-24.6.

Mathematics
2 answers:
zlopas [31]3 years ago
6 0

<u>Answer</u>

\boxed {y= -8.5}


<u>Solution & detailed explanation </u>

In this problem we are solving for y.


First, add 0.3 on both sides.

5.1 + 0.3= 5.4


Now you would need to subtract, 21.3 on both sides.

5.4y + 21.3= -24.6


-24.6 - 21.3= -45.9


Divide 5.4 on both sides.

5.4y = -45.9


Therefore, the answer would be \boxed {y= -8.5}







ivann1987 [24]3 years ago
3 0

To solve this equation, we will need to isolate y, the variable. These are the steps that follow:


1. Add 0.3y to each side.

2. Subtract 21.3 from each side.

3. Divide both sides by 5.4y.

Try and figure it out yourself! If you have trouble...


The answer is y = -8.5

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Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}

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  • {\dashrightarrow \sf {Time = 4 \: years}}
  • \dashrightarrow \sf{Rate = 30\%}
  • \begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}

  • \dashrightarrow{\sf{Simple \: Interest }}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}

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Where

  • \dashrightarrow{\sf{S.I = Simple \:  Interest }}
  • {\dashrightarrow{\sf{P = Principle }}}
  • {\dashrightarrow{\sf{ R = Rate }}}
  • {\dashrightarrow{\sf{T = Time}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{P \times R \times T}{100}}}}}}

Substituting the values

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 120}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{3600000}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\cancel{\dfrac{3600000}{100}}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{Rs.36000}}}}}

{\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}

  • Henceforth,The Simple Interest is Rs.36000..

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

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