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3 years ago

Solve the equation with a variable term on both sides: 5.1y+21.3=-0.3y-24.6.

Mathematics

2 answers:

zlopas [31]3 years ago

6 0

Answer

$\boxed {y= -8.5}$

Solution & detailed explanation

In this problem we are solving for y.

First, add 0.3 on both sides.

5.1 + 0.3= 5.4

Now you would need to subtract, 21.3 on both sides.

$5.4y + 21.3= -24.6$

-24.6 - 21.3= -45.9

Divide 5.4 on both sides.

$5.4y = -45.9$

Therefore, the answer would be $\boxed {y= -8.5}$

ivann1987 [24]3 years ago

3 0

To solve this equation, we will need to isolate y, the variable. These are the steps that follow:

1. Add 0.3y to each side.

2. Subtract 21.3 from each side.

3. Divide both sides by 5.4y.

Try and figure it out yourself! If you have trouble...

The answer is y = -8.5

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If you put $1,060 as a non-refundable deposit on an apartment, and pay $1,137 each month in rent, what is your total cost if you

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Answer:

$110,212

Step-by-step explanation:

$1,137*12=13,644. Multiply by 12 for 12 months in a year

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109,152+1060=110,212. Total Cost for 8 Years

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3 years ago

Three out of every five students wore green on St. Patricks day. What percent of the students wore green?

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60% of the students wore green

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3 years ago

Read 2 more answers

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

I will try to give as many details as possible.

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$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

3 years ago

A cyclist travels 20 miles in the same amount of time it takes a hiker to walk 6 miles. The rate of the cyclist is 7 mph faster

Anna11 [10]

Answer:

The speed of the cyclist is 10 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by cyclist = $D_1$ = 20 miles

The distance cover by biker = $D_2$ = 6 miles

The speed of biker = $S_2$ = s mph

The speed of cyclist = $S_1$ = 7 + s mph

The time taken by both cyclist and biker = t hour

Now. Distance = Speed × Time

So, $D_1$ = $S_1$ × t

Or, 20 = s × t

Or, t = $\frac{20}{7+s}$ .....1

And ,

$D_2$ = $S_2$ × t

or, 6 = s t

Or, t = $\frac{6}{s}$ ....2

From Eq 1 and 2

I.e $\frac{20}{7+s}$ = $\frac{6}{s}$

Or, 20 s = 6 ( 7 + s )

Or, 20 s - 6 s = 42

Or, 14 s = 42

∴ s = $\frac{42}{14}$

I,e s = 3 miles per hour

So, The speed of biker = $S_2$ = s = 3 miles per hour

And The speed of cyclist = $S_1$ = 7 + s = 7 + 3= 10 miles per hour

Hence The speed of the cyclist is 10 miles per hour . Answer

4 0

3 years ago

A television screen, length is 16 1/2 inches, width is w inches, and area is 462 square inches. Select all THREE equations that

tatiyna

Answer:

it's B, C, and D

Step-by-step explanation:

A. w ⋅ 462 = 16 1/2

not A

w * a ≠ l

B. 16 1/2 ⋅ w = 462

is B

l * w = a

C. 462 ÷ 16 1/2 = w

is C

a / l = w

D. 462 ÷ w = 16 1/2

is D

a / w = l

E. 16 1/2 ⋅ 462 = w

not E

l * a ≠ w

3 0

2 years ago