Ya, calculus and related rates, such fun!
everything is changing with respect to t
altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min
area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min
base=db/dt
alright
area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt
ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b
so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min
therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt
the base is decreasing at 1.6cm/min
Answer:
One solution: 0x + 0.5y = 0
Step-by-step explanation:
9x + 4y = 36
6x + 2.5y = 24
2 * Eq. 1
18x + 8y = 72
-3 * Eq. 2
-18x - 7.5y = -72
Add the multiples of the equations.
0x + 0.5y = 0
Answer: One solution: 0x + 0.5y = 0
We can't say. You never told us how side-b is related to side-a.
Are they in the same square ? Are they in the same triangle ?
Are they sides of the same box ? Are they on the same planet ?
2 to the power of 14 means 2^14.
That would be 16384.
1/3 divided by 6 can be thought of as 1/3 times 1/6 which equals our answer 1/18
