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Anit [1.1K]
3 years ago
5

Which is traveling faster, a car whose velocity vector is 201 + 25), or a car whose velocity vector is 30i, assuming that the un

its are the same for both directions? is the faster car. At what speed is the faster car traveling? speed = Enter the speed as a NUMBER, using exact values or at least 4 decimal place accuracy.
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0

Answer:

2nd car is running faster than the first car by 2.01 units.

Step-by-step explanation:

Let's assume that

  • the velocity of first car,

v_1\ =\ 20i\ +\ 25j

  • and the velocity of second car

v_2\ =\ 30i

=> speed of first car,

u_1\ =\ \sqrt{(20)^2+(25)^2}

      =\ \sqrt{400+625}

       =\ \sqrt{1025}

       = 32.01 units

and speed of second car,

u_2\ =\ \sqrt{(30)^2+(0)^2}

        = 30 units

u_2\ -\ u_1\ =\ 32.01\ -30

               = 2.01 units

Hence, 2nd car is running faster than the first car by 2.01 units.

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Determine whether the improper integral converges or diverges, and find the value of each that converges.
Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

u=x             dv=e^(2x)\cdot{dx}

du=dx         v=2\cdot{e^(2x)}

\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du

\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx

\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C

We can therefore determine that if x tends to 0 the limit is -1

\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1

5 0
3 years ago
Supongamos que estás en el infierno y el diablo te reta a un juego. Él piensa en un número natural.Cada día, tú tendrás una opor
Blababa [14]

Answer:

En síntesis, se inicia con el número natural más pequeño en el primer y se prosigue con los números siguientes en caso de no dar con n, de modo que el participante pasará en el infierno únicamente n días, algo pequeño en comparación con la eternidad.

Step-by-step explanation:

Los números naturales comprenden el subconjunto más pequeño de los números reales conformado por los siguientes elementos:

\mathbb{N} = \{1,2,3,4,...\}

Sea n \in \mathbb{N} el número que tiene el diablo en su mente, tal que n \geq 1. Comenzamos el primer día con 1, si este no corresponde con n. Entonces se utiliza 2 al día siguiente y este no corresponde, se emplea al día siguiente y así sucesivamente hasta conseguir n.

En síntesis, se inicia con el número natural más pequeño en el primer y se prosigue con los números siguientes en caso de no dar con n, de modo que el participante pasará en el infierno únicamente n días, algo pequeño en comparación con la eternidad.

6 0
3 years ago
sophie was 28 years old when daughter Nichole was born. In how many years will Sophie be two years less than still times Nichole
Kamila [148]
It will take 6 years for that to happen. 

You can find this by setting Nichole's age as x and Sophie's age as x + 28 since she will always be 28 years older. 

Now we are looking for a time that Sophie's age is equal to 2 less than 6 times Nichole's age. So we can set up the below equation. 

6(x) - 2 = x + 28
6x - 2 = x + 28
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This let's us know that it needs to be when Nichole is 6, which is 6 years in the future. 
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3 years ago
(x2 + 4)(x2 - 4) please help
VikaD [51]

(x^{2} + 4)(x^{2} - 4)

To solve this question you must FOIL (First, Outside, Inside, Last) like so

First:

(x^2 + 4)(x^2 - 4)

x^2 * x^2

x^4

Outside:

(x^2 + 4)(x^2 - 4)

x^2 * -4

-4x^2

Inside:

(x^2 + 4)(x^2 - 4)

4 * x^2

4x^2

Last:

(x^2 + 4)(x^2 - 4)

4 * -4

-16

Now combine all the products of the FOIL together like so...

x^4 - 4x^2 +4x^2 - 16

Combine like terms:

x^4 - 4x^2 +4x^2 - 16

- 4x^2 +4x^2 = 0

x^4 - 16 <<<This is your answer

Hope this helped!

~Just a girl in love with Shawn Mendes

4 0
3 years ago
Solve the following system of equations by graphing and select the correct answer below:
LUCKY_DIMON [66]
The only answer is x = 4, y = 2, 
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the graph is so easy, please try!!
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3 years ago
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