I WILL GIVE BRAINLIEST JUST HELP PLZZ

What’s the answer to this please? Thanks!

Serjik [45]

Answer:

70

beacuse (2x-35)+75=180
(2x-35)=105
2x=140
x=70

3 0

2 years ago

Which two substances bind using a lock-and-key mechanism?

kherson [118]

Answer:

enzyme and substrate. reactant and substrate. substrate and product.

Step-by-step explanation:

4 0

2 years ago

Given the following system of equations:

kompoz [17]

Answer:

(D) Divide the first equation, $-4x + 8y = 16$ , by 2.

Step-by-step explanation:

Given:

$-4x + 8y = 16 \ \ \ \ equation \ 1$

$2x + 4y = 8 \ \ \ \ equation \ 2$

We need to find the operation performed on equation so as to get resultant equation as:

$-2x + 4y = 8$

$2x + 4y = 8$

From Above we can see that there is no change in equation 2 with respect to resultant equation.

Also Resultant equation is simplified form of equation 1.

Simplifying equation 1 we get;

$-4x + 8y = 16$

We can see that 2 is the common multiple on both side.

Hence we will divide equation 1 with 2 we get

$\frac{-4x}{2}+\frac{8y}{2}=\frac{16}{2}\\\\-2x+4y=8$

which is the resultant equation.

Hence (D) Divide the first equation, $-4x + 8y = 16$ , by 2 is the correct option.

3 0

2 years ago

Triangle X Y Z is shown. Angle X Y Z is 51 degrees and angle Y Z X is 76 degrees. The length of X Z is 2.6, the length of X Y is

Novay_Z [31]

Answer:

3.2 units

Step-by-step explanation:

Use the law of sines

z/sin 76 = 2.6/sin 51

z = 2.6 sin 76/sin 51 = 3.2

4 0

2 years ago

After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i

Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume ( $V$ ) is calculated by:

$V = \frac{4\pi}{3}\cdot R^{3}$

Where $R$ is the radius of the tumor.

The percentage decrease in the volume of the tumor ( $\%V$ ) is expressed by:

$\%V = \frac{\Delta V}{V_{o}} \times 100\,\%$

Where:

$\Delta V$ - Absolute decrease in the volume of the tumor.

$V_{o}$ - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

$\Delta V = V_{o}-V_{f}$

$\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})$

The percentage decrease is finally simplified:

$\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%$

Given that $R_{o} = R$ and $R_{f} = 0.77\cdot R$ , the percentage decrease in the volume of tumor is:

$\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%$

$\%V = 54.34\,\%$

The volume of the tumor experimented a decrease of 54.34 percent.

5 0

2 years ago