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3 years ago

10. A rectangle has an area of 45m2

Mathematics

1 answer:

andrezito [222]3 years ago

5 0

Answer:

90 m^2

Step-by-step explanation:

Area = l*w

45 = l*15

Divide each side by 15

45/15 = l*15/15

3 =l

We want 2 *(l*w)

2 * (3*15)

2 *(45)

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Answer:

A and D

explanation:

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3 years ago

What is the approximate area of the shaded portion of the diagram? (Use 3.14 as an estimate for pi.)

Nadusha1986 [10]

Answer:

218

Step-by-step explanation:

first find the area of the circle-

$A=\pi r^{2} \\A=\pi 10^{2} \\A=100\pi \\A=314$

to find the area of the triangle, we need the base and the height. The base we know is 16, since we don't know the height yet, use the Pythagorean theorem to find the height. One leg is 16 the hypotenuse is 20 (2* the radius).

$a^{2} +b^{2} =c^{2} \\a^{2} +16^{2} =20^{2} \\a^{2} +256=400\\a^{2} =144\\a=12$

Now I know the height is 12. Find the area of the triangle

$A=\frac{1}{2} bh\\A=\frac{1}{2} (16)(20)\\A=96$

subtract the area of the triangle from the area of the circle

314-96=218

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3 years ago

Which number should be added to both sides of the equation to complete the square x^2-10x=7

mixer [17]

Answer:

Step-by-step explanation:

The number that needs to be added is the square of half the x-coefficient:

(-10/2)^2 = 25

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Adding that gives ...

(x -5)^2 = 32

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3 years ago

A zookeeper predicted that the weight of a newborn lion would be 2.8 pounds. When the zoo’s lion gave birth, the newborn weighed

Nonamiya [84]

3.5 - 2.8 is 0.7 so the zookeerper was 0.7 pounds off

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3 years ago

Read 2 more answers

A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one

d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

$P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855$

The probability that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

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3 years ago