Are these triangles congruent? If so, name the triangle congruence method.
1 answer:
You might be interested in
The first thing I did was plot the given two points: (3,0) and (0,4). I connected the two hollow dots and created a line. Then, I shaded the region below the line as mentioned in the problem. The result is show in the picture.
The detail about dashed line is important because it expresses an equality with a symbol < or >. The data points that coincide with that line is not part of the solution but just stand as a boundary, hence, I used dashed line and hollow points. If it were ≥ or ≤, then we use solid lines and dots. With that, we can already eliminate choice D.
Next, we test the inequality. Let's choose a point within the shaded region. Suppose the point is (1,0) denoted by the red dot. If it is part of the solution, then the inequality will be proven true.
<span>A. 4x-3y>-12
4(1) - 3(0) > -12
4 > -12, this is true
B. x+4y>4
1 + 4(0) > 4
1 > 4, this is not true
C. 4x-2y<-8
4(1) -2(0) < -8
4 <-8, this is not true
</span>∴The answer is A.<span>
</span>
The detail about dashed line is important because it expresses an equality with a symbol < or >. The data points that coincide with that line is not part of the solution but just stand as a boundary, hence, I used dashed line and hollow points. If it were ≥ or ≤, then we use solid lines and dots. With that, we can already eliminate choice D.
Next, we test the inequality. Let's choose a point within the shaded region. Suppose the point is (1,0) denoted by the red dot. If it is part of the solution, then the inequality will be proven true.
<span>A. 4x-3y>-12
4(1) - 3(0) > -12
4 > -12, this is true
B. x+4y>4
1 + 4(0) > 4
1 > 4, this is not true
C. 4x-2y<-8
4(1) -2(0) < -8
4 <-8, this is not true
</span>∴The answer is A.<span>
</span>
Answer:
1) The factors of are
Option C is correct.
3) The factors of are
Option B is correct.
Step-by-step explanation:
1) Factor :
For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.
The middle term : -3x
We can break them as (-2x)( -x)
Solving:
So, factors of are
Option C is correct.
3) Factor:
For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.
The middle term : 2x
We can break them as (4x)( -2x)
Solving
So, factors of are
Option B is correct.