The median would be 27.
The median of a data set is the middle number in the set. Therefore, if you want to calculate the median of a data set you must first order the values from least to greatest. Then find the middle number and that is the median.
2, 8, 19, 27, 31, 51, 3335
There are millions of solutions I’d recommend going to desmos and putting in a polynomial to find out if it does
Answer:
(a) 11.75%
(b) Profit decreases by $5.88 per calculator.
Step-by-step explanation:
(a) The percentage of failures with time is given by the following expression:
![f(x) = 0.125*e^{-0.125x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%200.125%2Ae%5E%7B-0.125x%7D)
Integrating this function from x = 0 to x = 1 year, gives us the percentage of failures in the first year:
![\int\limits^1_0 {f(x)} \, dx = F(x)=-e^{-0.125x}|_0^1\\F(1) = -e^{-0.125*1}-(-e^{-0.125*0}) = 1-e^{-0.125}\\F(1) =0.1175](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_0%20%7Bf%28x%29%7D%20%5C%2C%20dx%20%3D%20F%28x%29%3D-e%5E%7B-0.125x%7D%7C_0%5E1%5C%5CF%281%29%20%3D%20-e%5E%7B-0.125%2A1%7D-%28-e%5E%7B-0.125%2A0%7D%29%20%3D%201-e%5E%7B-0.125%7D%5C%5CF%281%29%20%3D0.1175)
11.75% of the calculators will fail within the warranty period.
(b) If the cost of a calculator is $50, and the profit per sale is $25, the average revenue per calculator is $75. Considering no income in failed calculators, the new cost per calculator is:
![C =\$50*(1+0.1175)\\C=\$55.88](https://tex.z-dn.net/?f=C%20%3D%5C%2450%2A%281%2B0.1175%29%5C%5CC%3D%5C%2455.88)
The effect of warranty replacement on profit is given by the difference in cost per calculator:
![\Delta P= \$50-\$55.88=-\$5.88](https://tex.z-dn.net/?f=%5CDelta%20P%3D%20%5C%2450-%5C%2455.88%3D-%5C%245.88)
Profit decreases by $5.88 per calculator.
Answer:
s and t are perpendicular
Step-by-step explanation:
they intersect at a 90 degree angle, which is marked by the little square at the point where they intersect.
The answer is B y = 5x - 14