(2)^3 * (5)^2 * 11
We use PEMDAS so we have to do the exponents first.
2^3 = 8
5^2 = 25
8 * 25 *11
You then go left to right cause they are all multiplication:
200 *11 = 2200 miles
Since
is negative, it doesn't have any real roots.
Answer:
<h2>
∠PQT = 72°</h2>
Step-by-step explanation:
According to the diagram shown, ∠OPQ = ∠OQP = 18°. If PQT is a tangent to the circle, it can be inferred that line OQ is perpendicular to line QT. Ths shows that ∠OQT = 90°.
Also from the diagram, ∠OQP + ∠PQT = ∠OQT;
∠PQT = ∠OQT - ∠OQP
Given ∠OQP = 18° and ∠OQT = 90°
∠PQT = 90°-18°
∠PQT = 72°
Answer:
The first answer is correct.
(x + 1)^2 + (y - 2)^2 = 1
A circle with the midpoint M(Mx, My) and the radius r can be written as
(x - Mx)^2 + (y - My)^2 = r^2
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D. Pyramid
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