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3 years ago

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Which choices are equivalent to the exponential expression below? Check all that apply . (4/5) ^ 3 B. 64/125 (4/5)(4/5) + (4/5)

3(4/5) 12/15 16/25 (4 ^ 3)/(5 ^ 3)

2 answers:

Dmitrij [34]3 years ago

4 0

Answer:

B) 64/125

Step-by-step explanation:

quester [9]3 years ago

3 0

Answer:

B) 64/125

Step-by-step explanation:

your welcome

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Need help on 6 and 7 asap! Will mark brainliest!!

MrMuchimi

I did number 6 to give you an idea of what you have to do. First find simplify the top and bottom and reduce!

Hope it helps! Comment if you have any questions!

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3 years ago

Read 2 more answers

In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 4x – 5, and HE = 2y + 3. Find the values of x and y.

marissa [1.9K]

Here, DH = HF

x+3 = 3y

x = 3y-3 ----(I)

GH = HE

4x-5 = 2y+3

4x = 2y+8

Substitute value of x,

4(3y-3) = 2y+8

12y-12 = 2y+8

12y-2y = 12+8

10y = 20

y = 2

Now, substitute it in equation 1,

x = 3(2)-3

x = 6-3 = 3

So, your final answer is x=3 & y=2

3 0

3 years ago

Read 2 more answers

Either enter an exact answer in terms of \piπpi or use 3.14, point, 14 for \piπpi and enter your answer as a decimal.

OverLord2011 [107]

Answer:

49π sq. units

Step-by-step explanation:

Find the diagram attached

We can find the area of the given circle

Given

diameter of the circle d = 14

Area of the circle = πd²/4

Substitute the given diameter

Area of the circle = π(14)²/4

Area of the circle = 196π/4

Area of the circle = 49π sq. units

Hence the exact answer in terms of π is 49π sq. units

4 0

2 years ago

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$

Since

$\int\limits^1_0 {x^{2} } \, dx = 13$ ,

Substituting this into the equation the equation, we have

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Learn more about definite integrals here:

brainly.com/question/17074932

4 0

2 years ago

Part A: Describe how you can decompose this shape into triangles. (2 points)

kvv77 [185]

Answer:

A: 6 triangles with height 10.4 inches each and base 12 inche

B: 62.4 square inches

C: 374.4 square inches

Step-by-step explanation:

Part A: You can form a triangle by connecting E to the top of the segment and connecting the top of the segment to D. Recreating this with each section will create 6 triangles with height 10.4 inches each and base 12 inches.

Part B: The area of a triangle is A = 1/2b*h. Substitute h = 10.4 and b = 12.

A = 1/2*10.4*12 = 62.4

Part C: There are 6 triangles each with area 62.4. So the area of the whole figure will be 6*62.4 = 374.4.

8 0

3 years ago