Question

max is making a rectangular garden that is 5 feet less than twice its width. If the perimeter of the garden is 80 feet, what will be its dimensions?

Answer 1

L=2w-5

2(l+w)=80
l+w=40
2w-5+w=40
3w=45
w=15 feet
l=25 feet. As a result, the width is 15 feet and length is 25 feet. Hope it help!

Answer 2

Answer:

Length = 25 feet and width = 15 feet

Step-by-step explanation:

MAx is making a rectangular garden that is 5 feet less than twice its width

LEt w be the width of the garden.

Length is 5 feet less than twice its width

So length of the garden = $2w-5$

Perimeter of the garden is 80 feet

Perimeter of rectangle = $2(length ) + 2(width)$

$80=2(2w-5) + 2(w)$, solve for w

$80=4w-10 + 2(w)$

$80=6w-10$

Add 10 on both sides

$90=6w$, divide both sides by 6

w=15

$L=2w-5=2(15)-5= 30-5=25$

So Length = 25 feet and width = 15 feet