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3 years ago

What is the slope of the line that contain the points (2, 1) and (-3, 4)?

Mathematics

1 answer:

kotykmax [81]3 years ago

5 0

-3/5 :)

Y2-Y1/X2-X1= slope

4-1/-3-2= 3/-5 so the slope is -3/5 :) .

hope this helped, goodluck <3

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What is the solution to -2(4x + 8) 4(2 - x)?

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Write the slope intercept form Through:(1,-5) and(4, -1)

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Slope intercept form is

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3 years ago

Which is equivalent to <img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B9%7D%20%5E%7B%5Cfrac%7B1%7D%7B2%7Dx%20%7D" id="TexForm

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Option B

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3 years ago

93 points if you answer.

Nutka1998 [239]

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3 years ago

Read 2 more answers

Write the equation in siope-intercept form for the line that passes through the given pointand is perpendicular to the given equ

yulyashka [42]

For a line in the form:

$\begin{gathered} ax+by=c \\ The\text{ slope m is:} \\ m=-\frac{a}{b} \end{gathered}$

In this case, for the line 2x + 10y = 20 with a=2 and b=10 the slope is:

$\begin{gathered} m_1=-\frac{a}{b}=-\frac{2}{10} \\ m_1=-\frac{1}{5} \end{gathered}$

Now, two lines are perpendiculars if the slopes satisfy the following equation:

$m_2=-\frac{1}{m_1}$

So, for the line we want the slope is:

$\begin{gathered} m_1=-\frac{1}{5} \\ m_2=-\frac{1}{m_1}=-\frac{1}{(-\frac{1}{5})}=5 \end{gathered}$

Finally, the line pass througth the point (2, 3) with slope m=5, so the equation is:

$\begin{gathered} P_1=(2,3),m=5 \\ y=mx+b \\ \text{The P1 must satisfy the equation:} \\ 3=5\cdot2+b \\ b=3-10 \\ b=-7 \end{gathered}$

The equation of the line is y = 5x - 7

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1 year ago