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3 years ago

a coin is tossed, then a letter in the word accomplishment is chosen at random. find the probability of heads, then a vowel

Mathematics

1 answer:

emmasim [6.3K]3 years ago

4 0

Answer:

$\frac{5}{52}$

Step-by-step explanation:

Coin toss:

$Total\ outcome=\{H,T\}\\\\Favourable\ outcome=\{H\}\\\\P(Head)=\frac{Favourable\ outcome}{Number\ of\ total\ outcome}\\\\P(Head)=\frac{1}{2}$

Letter Selection:

$Number\ of\ total\ outcomes=26\ \ \ \ \ \ \ as\ total\ letters\ are\ 26\\\\Favourable\ outcomes=5\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ as\ there\ are\ 5\ vowels\\\\P(vowel)=\frac{Favourable\ outcomes}{Number\ of\ total\ outcomes}\\\\P(vowel)=\frac{5}{26}$

$These\ two\ events\ are\ independent.\\\\Hence\ probability\ of\ head\ and\ then\ vowel=\frac{1}{2}\times \frac{5}{26}=\frac{5}{52}$

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7. All of the following are perfect square trinomials EXCEPT one. Which is it?

wolverine [178]

Answer:

All answers EXCEPT answer C. are perfect square trinomials.

Step-by-step explanation:

A perfect square trinomial is polynomial that satisfies the following condition:

$(a+b)^{2} = a^{2}+2\cdot a \cdot b + b^{2}$ , $\forall\,a,b\in\mathbb{R}$

Let prove if each option observe this:

a) $4\cdot x^{2} + 12\cdot x\cdot y + 9\cdot y^{2}$

1) $4\cdot x^{2} + 12\cdot x\cdot y + 9\cdot y^{2}$ Given

2) $(2\cdot x)^{2}+ 2\cdot (2\cdot x)\cdot (3\cdot y)+(3\cdot y)^{2}$ Definition of power/Distributive, associative and commutative properties.

3) $a = 2\cdot x$ , $b = 3\cdot y$ Definition of perfect square trinomial/Result.

b) $9\cdot a^{2}-36\cdot a + 36$

1) $9\cdot a^{2}-36\cdot a + 36$ Given.

2) $(3\cdot a)^{2}-2\cdot (3\cdot a)\cdot 6 + 6^{2}$ Definition of power/Distributive, associative and commutative properties.

3) $a = 3\cdot a$ , $b = 6$ Definition of perfect square trinomial/Result.

c) $x\cdot y^{2}-4\cdot x^{2}\cdot y^{2}+4\cdot x^{2}\cdot y^{2}$

1) $x\cdot y^{2}-4\cdot x^{2}\cdot y^{2}+4\cdot x^{2}\cdot y^{2}$ Given

2) $x\cdot y\cdot (1-4\cdot x+4\cdot x)$ Distributive property.

3) $x\cdot y \cdot 1$ Existence of the additive inverse/Modulative property.

4) $x\cdot y$ Modulative property/Result.

d) $a^{2}\cdot b^{2}+4\cdot a^{3}\cdot b + 4\cdot a^{4}$

1) $a^{2}\cdot b^{2}+4\cdot a^{3}\cdot b + 4\cdot a^{4}$ Given

2) $(a\cdot b)^{2}+2\cdot (a\cdot b)\cdot (2\cdot a^{2})+(2\cdot a^{2})$ Definition of power/Distributive, associative and commutative properties.

3) $a = a\cdot b$ , $b = 2\cdot a^{2}$ Definition of perfect square trinomial.

All answers EXCEPT answer C. are perfect square trinomials.

8 0

3 years ago

A swimming pool is 65.25 feet long and 40.5 feet wide. How much longer is the pool than it is wide? 24.35 105.75 1.61 24.75

Tanya [424]

Answer:

D. 24.75

Explanation:

literally just subtract 65.25 by 40.5 ??

8 0

2 years ago

christine's weekly salary is $358. she pays $53.70 for federal income tax and $17.90 for state income tax and $17.90 for state i

Alexandra [31]

It would be 46 for the salary and for the income would be 35 because if u subtract that and then divide it u get 50

4 0

2 years ago

If 3x + 7y = 47, AND 2x - y = 3 What is the value x?

elixir [45]

X=4
y=5
work shown below

4 0

2 years ago

Barbara drives between Miami, Florida, and West Palm Beach, Florida. She drives 50 mi in clear weather and then encounters a thu

cluponka [151]

Answer:

Her speed driving in nice weather is 50 mph and in thunderstorm is 32 mph.

Step-by-step explanation:

Barbara drives 50 miles in clear weather and then encounters a thunderstorm for the last 16 miles.

Suppose, her speed in nice weather is $x$ mph.

As she drives 18 mph slower through the thunderstorm than she does in clear weather, so her speed in thunderstorm will be: $(x-18) mph$

We know that, $Time = \frac{Distance}{Speed}$

So, the time of driving in clear weather $=\frac{50}{x}$ hours

and the time of driving in thunderstorm $=\frac{16}{x-18}$ hours.

Given that, the total time for the trip is 1.5 hours. So, the equation will be......

$\frac{50}{x}+ \frac{16}{x-18}=1.5 \\ \\ \frac{50x-900+16x}{x(x-18)}=1.5\\ \\ \frac{66x-900}{x(x-18)}=1.5 \\ \\ 1.5x(x-18)=66x-900\\ \\ 1.5x^2-27x=66x-900\\ \\ 1.5x^2-93x+900=0\\ \\ 1.5(x^2 -62x+600)=0\\ \\ x^2 -62x+600=0\\ \\ (x-50)(x-12)=0$

Using zero-product property.........

$x-50=0\\ x=50\\ \\ and\\ \\ x-12=0\\ x=12$

We need to ignore $x=12$ here, otherwise the speed in thunderstorm will become negative.

So, her speed driving in nice weather is 50 mph and her speed driving in thunderstorm is (50-18) = 32 mph

3 0

3 years ago